Chapter 1, Problem 26QP

Interpretation Introduction

Interpretation: The temperature givenin Celsius is to be converted to Fahrenheit and that given inFahrenheit is to be converted to Celsius.

Concept Introduction:

The temperature in Celsius can be converted to Fahrenheit as follows:

${}^{\circ }\text{F}=\frac{9^{\circ }\text{F}}{5^{\circ }\text{C}}\times \left({}^{\circ }\text{C}\right)+{32}^{\circ }\text{F}$

The temperature in Fahrenheit can be converted to Celsius as follows:

${}^{\circ }\text{C}=\frac{5^{\circ }\text{C}}{9^{\circ }\text{F}}\left({}^{\circ }\text{F}-{32}^{\circ }\text{F}\right)$