Chapter 1, Problem 1E.17E

(a)

Interpretation Introduction

Interpretation:

The type of orbital of ground state germanium atom from which an electron will be removed to form $+1ion$ has to be written.

Concept Introduction:

Electronic configuration: The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is $s,p,dandf.$  The lowest energy orbital is $ls.$

The energy order of the orbital for the first three periods is as follows,

    $ls,2s,2p,3s,and3p.$

The orbital which is closer to the nucleus has lower energy; therefore the $2s$ is lower in energy than $3s.$   Accordingly $2s$ is lower in energy than $2pand4s$ is lower in energy than $3d.$

In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below,

$ls,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p,8s,\mathrm{...}$

(b)

Interpretation Introduction

Interpretation:

The type of orbital of ground state manganese atom from which an electron will be removed to form $+1ion$ has to be written.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The type of orbital of ground state barium atom from which an electron will be removed to form $+1ion$ has to be written.

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The type of orbital of ground state gold atom from which an electron will be removed to form $+1ion$ has to be written.

Concept Introduction:

Refer to part (a).