Chapter 1, Problem 1B.6E

Interpretation Introduction

Interpretation:

The energy change resulting from the emission of $1.00mol$ of photons at the wavelength of $865nm$ has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

  $E=h\nu =\frac{hc}{\lambda }$

Where, h is the Planck’s constant, $\nu$ is the frequency of radiation, $c$ is the speed of light and $\lambda$ is the wavelength of the radiation.