Concept explainers
Videos
(a)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structures are not resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
The two structures have completely different carbon skeleton. The first one has a six membered ring while the second has a seven membered ring. Since these two structures do not have the same position of the atoms, they cannot be resonance structures.
From the position of atoms and electrons, it is found that the given pair is not resonance structures of one another.
(b)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
In these two structures, the position of the hydrogen atoms is not the same. Hence, these structures cannot be resonance structures of each other.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
(c)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are as shown below.
To obtain the second resonance structure, two curved arrows are drawn and the electrons are moved accordingly. The two structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(d)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
To obtain the second resonance structure, two curved arrows are drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(e)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
To obtain the second resonance structure, a curved arrow is drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(f)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
(g)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(h)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.
Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is different; at the same time, one H atom changes its position. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
Want to see more full solutions like this?
Chapter 1 Solutions
Organic Chemistry: Principles And Mechanisms (second Edition)
- Write the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 5 6 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! ☐arrow_forwardCompare these chromatograms of three anti-psychotic drugs done by HPLC and SFC. Why is there the difference in separation time for SFC versus HPLC? Hint, use the Van Deemter plot as a guide in answering this question. Why, fundamentally, would you expect a faster separation for SFC than HPLC, in general?arrow_forwardA certain inorganic cation has an electrophoretic mobility of 5.27 x 10-4 cm2s-1V-1. The same ion has a diffusion coefficient of 9.5 x 10-6cm2s-1. If this ion is separated from cations by CZE with a 75cm capillary, what is the expected plate count, N, at an applied voltage of 15.0kV? Under these separation conditions, the electroosmotic flow rate was 0.85mm s-1 toward the cathode. If the detector was 50.0cm from the injection end of the capillary, how long would it take in minutes for the analyte cation to reach the detector after the field was applied?arrow_forward
- 2.arrow_forwardPlease solve for the following Electrochemistry that occursarrow_forwardCommercial bleach contains either chlorine or oxygen as an active ingredient. A commercial oxygenated bleach is much safer to handle and less likely to ruin your clothes. It is possible to determine the amount of active ingredient in an oxygenated bleach product by performing a redox titration. The balance reaction for such a titration is: 6H+ +5H2O2 +2MnO4- à 5O2 + 2Mn2+ + 8H2O If you performed the following procedure: “First, dilute the Seventh Generation Non-Chlorine Bleach by pipetting 10 mL of bleach in a 100 mL volumetric flask and filling the flask to the mark with distilled water. Next, pipet 10 mL of the diluted bleach solution into a 250 mL Erlenmeyer flask and add 20 mL of 1.0 M H2SO4 to the flask. This solution should be titrated with 0.0100 M KMnO4 solution.” It took 18.47mL of the KMnO4 to reach the endpoint on average. What was the concentration of H2O2 in the original bleach solution in weight % assuming the density of bleach is 1g/mL?arrow_forward
- 10.arrow_forwardProper care of pH electrodes: Why can you not store a pH electrode in distilled water? What must you instead store it in? Why?arrow_forwardWrite the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 569 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! §arrow_forward
- Identify the amino acids by name. Illustrate a titration curve for this tetrapeptide indicating the pKa's for each ionizable groups and identify the pI for this tetrapeptide. please helparrow_forward↓ ina xSign x Sign X labs X Intro X Cop Xa chat X My Cx Grac X Laur x Laur xash learning.com/ihub/assessment/f188d950-dd73-11e0-9572-0800200c9a66/d591b3f2-d5f7-4983-843c-0d00c1c0340b/f2b47861-07c4-4d1b-a1ee-e7db2 +949 pts /3400 K Question 16 of 34 > © Macmillan Learning Draw the major E2 reaction product formed when cis-1-chloro-2-ethylcyclohexane (shown) reacts with hydroxide ion in DMSO. H CH2CH3 H H HO- H H H Cl DMSO H H C Select Draw Templates More C H 0 2 Erasearrow_forwardA common buffer for stabilizing antibodies is 100 mM Histidine at pH 7.0. Describe the preparation of this buffer beginning with L-Histidine monohydrochloride monohydrate and 1 M NaOH. Be certain to show the buffering reaction that includes the conjugate acid and base.arrow_forward
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning