Organic Chemistry, Loose-leaf Version
Organic Chemistry, Loose-leaf Version
8th Edition
ISBN: 9781305865549
Author: William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher: Cengage Learning
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Chapter 1, Problem 1.64AP

(a)

Interpretation Introduction

Interpretation:

The reason has to explainfor the given molecule is impossible.

Concept introduction:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. 1. Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. 2. The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. 3. In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

According to the electron configuration the valence electron of carbon is four and the number of valence electron of hydrogen is one.

(b)

Interpretation Introduction

Interpretation:

The reason has to explain for the given molecule is impossible.

Concept introduction:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. 1. Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. 2. The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. 3. In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

According to the electron configuration the valence electron of carbon is four and the number of valence electron of hydrogen is one.

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Chapter 1 Solutions

Organic Chemistry, Loose-leaf Version

Ch. 1.3 - Prob. 1.11PCh. 1.3 - Prob. 1.12PCh. 1.4 - Predict all bond angles for these molecules. (a)...Ch. 1.5 - The geometry of carbon in diamond is tetrahedral,...Ch. 1.5 - Because of their spherical shape, C60 molecules...Ch. 1.5 - What best describes the CCC bond angles in C60? 1....Ch. 1.5 - Prob. 1.14PCh. 1.7 - Describe the bonding in these molecules in terms...Ch. 1.8 - Prob. 1.16PCh. 1.8 - Prob. 1.17PCh. 1.8 - Prob. 1.18PCh. 1.9 - Draw three contributing structures of the...Ch. 1.9 - What is the hybridization state of the circled...Ch. 1.9 - The molecule shown on the right in the example in...Ch. 1.9 - Prob. CQCh. 1.9 - The following structure is called imidazolium....Ch. 1 - Write the ground-state electron configuration for...Ch. 1 - Identify the atom that has each ground-state...Ch. 1 - Define valence shell and valence electron.Ch. 1 - How many electrons are in the valence shell of...Ch. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Write Lewis structures for these compounds. Show...Ch. 1 - Write Lewis structures for these ions. Show all...Ch. 1 - Prob. 1.29PCh. 1 - Some of these structural formulas are incorrect...Ch. 1 - Following the rule that each atom of carbon,...Ch. 1 - Following are several Lewis structures showing all...Ch. 1 - Which statements are true about electronegativity?...Ch. 1 - Why does fluorine, the element in the upper right...Ch. 1 - Arrange the single covalent bonds within each set...Ch. 1 - Using the values of electronegativity given in...Ch. 1 - Prob. 1.37PCh. 1 - Use VSEPR to predict bond angles about each...Ch. 1 - Use VSEPR to predict bond angles about each atom...Ch. 1 - Use VSEPR to predict the geometry of these ions....Ch. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - What is the meaning of the term tertiary (3) when...Ch. 1 - What is the meaning of the term tertiary (3) when...Ch. 1 - Draw structural formulas for (a) The four primary...Ch. 1 - Draw structural formulas for the three tertiary...Ch. 1 - Prob. 1.47PCh. 1 - Identify the functional groups in each compound.Ch. 1 - Draw a three-dimensional representation for each...Ch. 1 - Tetrafluoroethylene, C2F4, is the starting...Ch. 1 - Which statements are true about resonance...Ch. 1 - Prob. 1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Are the structures in each set valid contributing...Ch. 1 - State the orbital hybridization of each...Ch. 1 - Describe each highlighted bond in terms of the...Ch. 1 - Following is a structural formula of the...Ch. 1 - Draw a Lewis structure for methyl isocyanate,...Ch. 1 - What is the hybridization of the highlighted atoms...Ch. 1 - Using cartoon representations, draw a molecular...Ch. 1 - In what kind of orbitals do the lone-pair...Ch. 1 - Draw the delocalized molecular orbitals for the...Ch. 1 - Prob. 1.64APCh. 1 - Each compound contains both ions and covalent...Ch. 1 - Predict whether the carbon-metal bond in these...Ch. 1 - Prob. 1.67APCh. 1 - Phosphorus is immediately under nitrogen in the...Ch. 1 - Draw a Lewis structure for the azide ion, N3. (The...Ch. 1 - Cyanic acid, HOCN, and isocyanic acid, HNCO,...Ch. 1 - In Chapter 6, we study a group of organic cations...Ch. 1 - Many reactions involve a change in hybridization...Ch. 1 - Following is a structural formula of benzene,...Ch. 1 - Following are three contributing structures for...Ch. 1 - (a) Draw a Lewis structure for the ozone molecule,...Ch. 1 - The following two compounds are isomers; that is,...Ch. 1 - In future chapters, we will encounter...Ch. 1 - Prob. 1.78AP
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