Electric machinery fundamentals
5th Edition
ISBN: 9780073529547
Author: Chapman, Stephen J.
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 1, Problem 1.4P
A motor is supplying
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The hysteresis losses and eddy current losses in a dc machine running at 1000 rpm are 250 W and 100 W respectively. If the flux remains constant, at what speed will the total iron loss be halved?
The hysteresis and eddy current losses of a DC Machine running at 1000 rpm are 250 watts
and 100 watts, respectively. If the flux remains constant, at what speed will the total iron loss
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Chapter 1 Solutions
Electric machinery fundamentals
Ch. 1 - What is torque? What role does torque play in the...Ch. 1 - What is Amperes law?Ch. 1 - What is magnetizing intensity? What is magnetic...Ch. 1 - How does the magnetic circuit concept aid in the...Ch. 1 - What is reluctance?Ch. 1 - What is a ferromagnetic material? Why is the...Ch. 1 - How does the relative permeability of a...Ch. 1 - Prob. 1.8QCh. 1 - What are eddy current losses? What can be done to...Ch. 1 - Why are all cores exposed to ac flux variations...
Ch. 1 - What is Faraday law?Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - Prob. 1.14QCh. 1 - The linear machine in Figure 1-19 is running at...Ch. 1 - Just how does a decrease in flux produce an...Ch. 1 - Will current be leading or lagging voltage in an...Ch. 1 - What are real, reactive, and apparent power? What...Ch. 1 - What is power factor?Ch. 1 - Prob. 1.1PCh. 1 - A flywheel with a moment of inertia of 4kgm2 is...Ch. 1 - A force of 10 N is applied to a cylinder of radius...Ch. 1 - A motor is supplying 50Nm of torque to its load....Ch. 1 - A ferromagnetic core is shown in Figure P1-2. The...Ch. 1 - A ferromagnetic core with a relative permeability...Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A core with three legs is shown in Figure P1-5....Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A wire is shown in Figure P1-7 that is moving in...Ch. 1 - Repeat Problem 1-10 for the wire in Figure P1-8.Ch. 1 - Prob. 1.12PCh. 1 - A core with three legs is shown in Figure P1-10....Ch. 1 - A two-legged magnetic core with an air gap is...Ch. 1 - A transformer core with an effective mean path...Ch. 1 - The core shown in Figure P1-2 has the flux shown...Ch. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Demonstrate that Equation (1-59) can be derived...Ch. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - For the linear machine of Problem 1-22: When this...
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- A series motor develops 164 lb-ft torque when the current is 94A. If the load increases the current 50% with the flux increase of 20%, what is the torque at the second value of current?arrow_forwardA 255 V, DC lathe machine, (not a 2 pole machine) has armature resistance and series resistance are 0.150 and 1702 respectively. The motor has 25mWb flux per pole. The ratio of pole to parallel paths is unity. The product of this ratio and number of turns in armature section is 1000. When it runs light, it has a speed of 1200 rpm. If it runs at maximum load, it takes a current of 70A. (1) Which machine is this one, shunt or series ? Is machine lap wound or wave wound? (3) Calculate the no load back EMF. (4) Calculate the no load armature current. (5) Calculate the no load shunt current. (6) Calculate the current drawn by the machine. Calculate the variable losses on load. (8) Calculate the armature power when it runs light. (9) Calculate the stray losses when it runs light. (10) Calculate the full load armature current. (11) (12) (13) Calculate the full load back EMF. Calculate the Variable losses on maximum possible load. Calculate the armature power on maximum load. (14) Calculate…arrow_forwardIf rotor input of a SCIM running with a slip of 10% is 100 kW. gross power developed by its rotor is ..... kW a) 10 b) 90 c) 99 d) 80arrow_forward
- A 220 V DC Machine supplies 20 A at 200 V as a generator. The armature resistance is 0.2 ohm. If the machine is now operated as a motor at the same terminal voltage and current but with the flux increased by 10 percent, the ratio of motor speed to generator speed will bearrow_forward1. Knowing that a motor has a power P of 300 W, calculate the torque T that the motor must produce in order to rotate at a speed n of 1146 r/min. T= 1.79 N·m O T= 2.50 N•m O T= 5.33 N•m O T= 4.14 N-marrow_forwardA 550-V series motor takes 112A and operates at 820 r/min when the load is 75hp. if the effective armature-circuit resistance is 0.15 ohms calculate the horsepower output of the motor when the current drops to 84A, assuming that the flux is reduced by 15%arrow_forward
- Machine problemarrow_forwardaswer question 2arrow_forwardA DC series motor is running with a speed of 800 RPM, while taking a current of 20A from the supply. If the load is changed such that the current drawn by motor is increased to 50 A. Calculate the speed of the motor on new load. The armature and series field winding resistance are 0.2Ω and 0.3Ω respectively. Assume the flux produced is proportional to the current. Assume supply voltage is 250V.arrow_forward
- 128. The hysteresis loss of a dc machine is 300 W when the flux per pole is 30 mWb and the machine is driven at 1000 rpm. How much Is the loss If the field is adjusted to produce 50 mWb per pole whlle the speed Is reduced to 900 rpm? A. 420 W B. 510 W C. 450 W D. 500 Warrow_forwardA four pole machines generates 250V when operated at 1500 rpm. If the flux per pole is 1.85 x 106 maxwell, the number of armature slots is 45 and the armature winding has two parallel paths. If the speed of the generator is reduced to 1350 rpm, what would be the generated voltage. To what value of flux per pole should the excitation be adjusted if the generated voltage is to remain the same at 250Varrow_forwarddivided by rpm. Torque equals horsepower 5252 a. b. horsepower x 5252 voltage x horsepower C. d.arrow_forward
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