Chapter 1, Problem 1.3P

(a)

Interpretation Introduction

Interpretation:

It is to be shown that the given equation can be put in the equation of the form 1.54. Also, the equations for the virial coefficients $B,C,\text{ and }D$ in terms of the constants given in equation 1.61 are to be determined.

Concept Introduction:

Equation 1.54 to be used is:

  $z=\frac{p}{{\rho }_{M}RT}=1+{\rho }_{M}B+{\rho }_M^{2}C+{\rho }_M^{3}D$ ...... (1)

Here, ${\rho }_M$ is the molar density and $B,C,D$ are the virial coefficients. $p\text{ and }T$ are the pressure and temperature of the gas respectively, and $R$ is the universal gas constant.

(b)

Interpretation Introduction

Interpretation:

The values of the virial coefficients for air in SI units are to be calculated.

Concept Introduction:

Equation 1.54 to be used is:

  $z=\frac{p}{{\rho }_{M}RT}=1+{\rho }_{M}B+{\rho }_M^{2}C+{\rho }_M^{3}D$ ...... (1)

Here, ${\rho }_M$ is the molar density and $B,C,D$ are the virial coefficients. $p\text{ and }T$ are the pressure and temperature of the gas respectively, and $R$ is the universal gas constant.

(c)

Interpretation Introduction

Interpretation:

The value of $z$ for air at given conditions is to be calculated.

Concept Introduction:

Equation 1.54 to be used is:

  $z=\frac{p}{{\rho }_{M}RT}=1+{\rho }_{M}B+{\rho }_M^{2}C+{\rho }_M^{3}D$ ...... (1)

Here, ${\rho }_M$ is the molar density and $B,C,D$ are the virial coefficients. $p\text{ and }T$ are the pressure and temperature of the gas respectively, and $R$ is the universal gas constant.