(a) Calculate the rate of heat conduction through a double-paned window that has a 150-m 2 area and is made of two panes of 0.800 cm-thick glass separated by a 1.00 cm air gap. The inside surface temperature is 15.0 °C, while that on the outside is − 10.0 OC. ( Hint: There are identical temperature drops across the two glass panes. First find these and then the temperature drop across the air gap. This problem ignores the increased heat transfer in the air gap due to convection .) (b) Calculate the rate of heat conduction through a 1.60-cm-thick window of the same area and with the same temperatures. Compare your answer with that for part (a).
(a) Calculate the rate of heat conduction through a double-paned window that has a 150-m 2 area and is made of two panes of 0.800 cm-thick glass separated by a 1.00 cm air gap. The inside surface temperature is 15.0 °C, while that on the outside is − 10.0 OC. ( Hint: There are identical temperature drops across the two glass panes. First find these and then the temperature drop across the air gap. This problem ignores the increased heat transfer in the air gap due to convection .) (b) Calculate the rate of heat conduction through a 1.60-cm-thick window of the same area and with the same temperatures. Compare your answer with that for part (a).
(a) Calculate the rate of heat conduction through a double-paned window that has a 150-m2 area and is made of two panes of 0.800 cm-thick glass separated by a 1.00 cm air gap. The inside surface temperature is 15.0 °C, while that on the outside is
−
10.0 OC. (Hint: There are identical temperature drops across the two glass panes. First find these and then the temperature drop across the air gap. This problem ignores the increased heat transfer in the air gap due to convection.) (b) Calculate the rate of heat conduction through a 1.60-cm-thick window of the same area and with the same temperatures. Compare your answer with that for part (a).
A cylinder with a piston contains 0.153 mol of
nitrogen at a pressure of 1.83×105 Pa and a
temperature of 290 K. The nitrogen may be
treated as an ideal gas. The gas is first compressed
isobarically to half its original volume. It then
expands adiabatically back to its original volume,
and finally it is heated isochorically to its original
pressure.
Part A
Compute the temperature at the beginning of the adiabatic expansion.
Express your answer in kelvins.
ΕΠΙ ΑΣΦ
T₁ =
?
K
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Part B
Compute the temperature at the end of the adiabatic expansion.
Express your answer in kelvins.
Π ΑΣΦ
T₂ =
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Part C
Compute the minimum pressure.
Express your answer in pascals.
ΕΠΙ ΑΣΦ
P =
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?
?
K
Pa
Learning Goal:
To understand the meaning and the basic applications of
pV diagrams for an ideal gas.
As you know, the parameters of an ideal gas are
described by the equation
pV = nRT,
where p is the pressure of the gas, V is the volume of
the gas, n is the number of moles, R is the universal gas
constant, and T is the absolute temperature of the gas. It
follows that, for a portion of an ideal gas,
pV
= constant.
Τ
One can see that, if the amount of gas remains constant,
it is impossible to change just one parameter of the gas:
At least one more parameter would also change. For
instance, if the pressure of the gas is changed, we can
be sure that either the volume or the temperature of the
gas (or, maybe, both!) would also change.
To explore these changes, it is often convenient to draw a
graph showing one parameter as a function of the other.
Although there are many choices of axes, the most
common one is a plot of pressure as a function of
volume: a pV diagram.
In this problem, you…
Learning Goal:
To understand the meaning and the basic applications of
pV diagrams for an ideal gas.
As you know, the parameters of an ideal gas are
described by the equation
pV = nRT,
where p is the pressure of the gas, V is the volume of
the gas, n is the number of moles, R is the universal gas
constant, and T is the absolute temperature of the gas. It
follows that, for a portion of an ideal gas,
pV
= constant.
T
One can see that, if the amount of gas remains constant,
it is impossible to change just one parameter of the gas:
At least one more parameter would also change. For
instance, if the pressure of the gas is changed, we can
be sure that either the volume or the temperature of the
gas (or, maybe, both!) would also change.
To explore these changes, it is often convenient to draw a
graph showing one parameter as a function of the other.
Although there are many choices of axes, the most
common one is a plot of pressure as a function of
volume: a pV diagram.
In this problem, you…
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