Chapter 0, Problem 61PRT

To determine

To find: the odds of a penny of the given conditions. Write its simplest form.

Answer to Problem 61PRT

  $P\left(\text{odds of a pennies}\right)=2:3$ .

Explanation of Solution

Given:

The given condition is:

One coin is randomly selected from a jar containing 20 pennies, 15 nickels, 3 dimes, and 12 quarters.

Calculation:

Total number of jars containing pennies, nickels, dimes, and quarters is $20+15+12+3=50$ .

Total number of odd outcomes (exclude pennies) is $15+12+3=30$

Therefore, the odds of a pennies is

  $P\left(\text{odds of a pennies}\right)=\frac{20}{30}=\frac{2}{3}$

Hence, the simplest form of the odds of a dime is $P\left(\text{odds of a pennies}\right)=2:3$ .