Chapter 0, Problem 58POT

To determine

To find:the volume of the given cylinder.Round to the nearest tenth.

Answer to Problem 58POT

  $V=226.30inc{h}^3$ .

Explanation of Solution

Given:

The dimensions of the cylinderare

  $h=8inch,r=3inch$

Concept used:

Volume of the cylinder is given by

  $V=\pi r^{2}h$

Calculation:

As it is known that Volume of the cylinder is given by

  $V=\pi r^{2}h$

Therefore,

  $\begin{array}{l}V=\pi r^{2}h\\ =\frac{22}{7}\times {\left(3inch\right)}^2\times 8inch\\ =\frac{22}{7}\times 9inc{h}^2\times 8inch\\ =\frac{1584}{7}inc{h}^3\\ =226.28inc{h}^3\\ =226.30inc{h}^3\left\{\text{round up to nearest tenth}\right\}\end{array}$

Hence, the surface area of the given cylinder is $V=226.30inc{h}^3$ .