Chapter 0, Problem 45PRT

To determine

Find the area of triangle.

Answer to Problem 45PRT

  $Areaoftrinagle=18.64m^2$

Explanation of Solution

Given information:

  

Formula used:

Area of triangle= $\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$

Where a, b, and c are sides of triangle and $s=\frac{a+b+c}{2}$

As we know that 12,16 and 20 are sides of triangle, now by using $\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$ we will find area of triangle:

  $\begin{array}{l}s=\frac{a+b+c}{2}\\ s=\frac{4.3+8.7+10}{2}=\frac{23}{2}=11.5\end{array}$

  $\begin{array}{l}Areaoftrinagle=\sqrt{11.5\left(11.5-a\right)\left(11.5-b\right)\left(11.5-c\right)}\\ \\ Areaoftrinagle=\sqrt{11.5\left(11.5-10\right)\left(11.5-8.7\right)\left(11.5-4.3\right)}\\ \\ Areaoftrinagle=\sqrt{11.5\left(1.5\right)\left(2.8\right)\left(7.2\right)}\\ \\ Areaoftrinagle=\sqrt{347.76}\end{array}$

  $Areaoftrinagle=18.64m^2$