Chapter 0, Problem 42PRT

To determine

Find the area and perimeter.

Answer to Problem 42PRT

  $\begin{array}{l}Area=81inche{s}^2\\ Perimeter=36inches\end{array}$

Explanation of Solution

Given information:

  

Formula used:

  $\begin{array}{l}\text{Area of square= side}\times \text{side}\\ \\ \text{Perimeter of square= 4}\times \text{side}\end{array}$

As we can see the above figure has all the angle of ${90}^{°}$ therefore the above figure is Square with side= 9 inches

  $\begin{array}{l}\text{Area of square= side}\times \text{side}\\ \\ \text{Area of square}=9\times 9\\ \\ \text{Area of square}=81inche{s}^2\end{array}$

  $\begin{array}{l}\text{Perimeter of square= 4}\times \text{side}\\ \\ \text{Perimeter of square}=4\times 9\\ \\ \text{Perimeter of square}=36inches\end{array}$