Chapter 0, Problem 48PG

To determine

To solve the system of equations

Answer to Problem 48PG

  $m=4$ and $r=2$ are the solution of the equation

Explanation of Solution

Given information:

  $\begin{array}{l}2r+m=11\\ 6r-2m=-2\end{array}$

Calculation:

Let the given equation be (1) and (2) respectively.

Taking (1)

  $2r+m=11$

Rearranging,

  $m=11-2r$ (3)

Put m in equation (3)

  $6r-2(11-2r)=-2$

Solving,

  $6r-22+4r=-2$

So,

  $10r-22=-2$

Adding 22 to both sides,

  $10r-22+22=-2+22$

Now,

  $10r=20$

Dividing by 10,

  $r=2$

Put r in (3)

  $m=11-2(2)$

Solving,

  $m=11-4$

Hence, $m=4$ and $r=2$ are the solution of the equation.