Geometry, Student Edition

1st Edition

ISBN: 9780078884849

Author: McGraw-Hill, McGraw Hill

Publisher: Glencoe/McGraw-Hill School Pub Co

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Question

Chapter 0, Problem 33PG

To determine

To solve the inequality

Expert Solution & Answer

Answer to Problem 33PG

$k≥−75$ is the solution.

Explanation of Solution

Given information:

$−25k−20≤10$

Calculation:

The given inequality is $−25k−20≤10$

Solving the inequality by adding 20 to both sides of equation,

$−25k−20+20≤10+20$

So,

$−25k≤30$

Dividing by $−52$ ,

$−25k×(−52)≤30×(−52)$

When multiplied by a negative number, inequality is flipped.

$k≥−75$

Hence, $k≥−75$ is the solution of the inequality.

Chapter 0, Problem 32PG

Chapter 0, Problem 34PG

Chapter 0 Solutions

Geometry, Student Edition

Ch. 0.1 - Prob. 1E Ch. 0.1 - Prob. 2E Ch. 0.1 - Prob. 3E Ch. 0.1 - Prob. 4E Ch. 0.1 - Prob. 5E Ch. 0.1 - Prob. 6E Ch. 0.1 - Prob. 7E Ch. 0.1 - Prob. 8E Ch. 0.1 - Prob. 9E Ch. 0.1 - Prob. 10E

Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.1 - Prob. 13E Ch. 0.1 - Prob. 14E Ch. 0.1 - Prob. 15E Ch. 0.1 - Prob. 16E Ch. 0.1 - Prob. 17E Ch. 0.1 - Prob. 18E Ch. 0.1 - Prob. 19E Ch. 0.1 - Prob. 20E Ch. 0.1 - Prob. 21E Ch. 0.1 - Prob. 22E Ch. 0.1 - Prob. 23E Ch. 0.1 - Prob. 24E Ch. 0.1 - Prob. 25E Ch. 0.1 - Prob. 26E Ch. 0.1 - Prob. 27E Ch. 0.2 - Prob. 1E Ch. 0.2 - Prob. 2E Ch. 0.2 - Prob. 3E Ch. 0.2 - Prob. 4E Ch. 0.2 - Prob. 5E Ch. 0.2 - Prob. 6E Ch. 0.2 - Prob. 7E Ch. 0.2 - Prob. 8E Ch. 0.2 - Prob. 9E Ch. 0.2 - Prob. 10E Ch. 0.2 - Prob. 11E Ch. 0.2 - Prob. 12E Ch. 0.2 - Prob. 13E Ch. 0.2 - Prob. 14E Ch. 0.2 - Prob. 15E Ch. 0.2 - Prob. 16E Ch. 0.2 - Prob. 17E Ch. 0.2 - Prob. 18E Ch. 0.2 - Prob. 19E Ch. 0.2 - Prob. 20E Ch. 0.2 - Prob. 21E Ch. 0.3 - Prob. 1E Ch. 0.3 - Prob. 2E Ch. 0.3 - Prob. 3E Ch. 0.3 - Prob. 4E Ch. 0.3 - Prob. 5E Ch. 0.3 - Prob. 6E Ch. 0.3 - Prob. 7E Ch. 0.3 - Prob. 8E Ch. 0.3 - Prob. 9E Ch. 0.3 - Prob. 10E Ch. 0.3 - Prob. 11E Ch. 0.3 - Prob. 12E Ch. 0.3 - Prob. 13E Ch. 0.3 - 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