Geometry, Student Edition
1st Edition
ISBN: 9780078884849
Author: McGraw-Hill, McGraw Hill
Publisher: Glencoe/McGraw-Hill School Pub Co
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 0.8, Problem 9E
To determine
To solve the equations by graphing.
Expert Solution & Answer
Answer to Problem 9E
The solution is (4,1)
Explanation of Solution
Given information: The equations are,
Graph:
Red line represents
Green line represents
Calculation:
Concluding from the graph.
The two lines intersect at point,
(4,1)
Hence, the solution is (4,1)
Chapter 0 Solutions
Geometry, Student Edition
Ch. 0.1 - Prob. 1ECh. 0.1 - Prob. 2ECh. 0.1 - Prob. 3ECh. 0.1 - Prob. 4ECh. 0.1 - Prob. 5ECh. 0.1 - Prob. 6ECh. 0.1 - Prob. 7ECh. 0.1 - Prob. 8ECh. 0.1 - Prob. 9ECh. 0.1 - Prob. 10E
Ch. 0.1 - Prob. 11ECh. 0.1 - Prob. 12ECh. 0.1 - Prob. 13ECh. 0.1 - Prob. 14ECh. 0.1 - Prob. 15ECh. 0.1 - Prob. 16ECh. 0.1 - Prob. 17ECh. 0.1 - Prob. 18ECh. 0.1 - Prob. 19ECh. 0.1 - Prob. 20ECh. 0.1 - Prob. 21ECh. 0.1 - Prob. 22ECh. 0.1 - Prob. 23ECh. 0.1 - Prob. 24ECh. 0.1 - Prob. 25ECh. 0.1 - Prob. 26ECh. 0.1 - Prob. 27ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.2 - Prob. 19ECh. 0.2 - Prob. 20ECh. 0.2 - Prob. 21ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.4 - Prob. 8ECh. 0.4 - Prob. 9ECh. 0.4 - Prob. 10ECh. 0.4 - Prob. 11ECh. 0.4 - Prob. 12ECh. 0.5 - Prob. 1ECh. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.5 - Prob. 11ECh. 0.5 - Prob. 12ECh. 0.5 - Prob. 13ECh. 0.5 - Prob. 14ECh. 0.5 - Prob. 15ECh. 0.5 - Prob. 16ECh. 0.5 - Prob. 17ECh. 0.5 - Prob. 18ECh. 0.5 - Prob. 19ECh. 0.5 - Prob. 20ECh. 0.5 - Prob. 21ECh. 0.5 - Prob. 22ECh. 0.5 - Prob. 23ECh. 0.5 - Prob. 24ECh. 0.5 - Prob. 25ECh. 0.5 - Prob. 26ECh. 0.5 - Prob. 27ECh. 0.5 - Prob. 28ECh. 0.5 - Prob. 29ECh. 0.5 - Prob. 30ECh. 0.5 - Prob. 31ECh. 0.5 - Prob. 32ECh. 0.5 - Prob. 33ECh. 0.5 - Prob. 34ECh. 0.5 - Prob. 35ECh. 0.5 - Prob. 36ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Prob. 11ECh. 0.6 - Prob. 12ECh. 0.6 - Prob. 13ECh. 0.6 - Prob. 14ECh. 0.6 - Prob. 15ECh. 0.6 - Prob. 16ECh. 0.6 - Prob. 17ECh. 0.6 - Prob. 18ECh. 0.6 - Prob. 19ECh. 0.6 - Prob. 20ECh. 0.6 - Prob. 21ECh. 0.6 - Prob. 22ECh. 0.6 - Prob. 23ECh. 0.6 - Prob. 24ECh. 0.7 - Prob. 1ECh. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0.7 - Prob. 10ECh. 0.7 - Prob. 11ECh. 0.7 - Prob. 12ECh. 0.7 - Prob. 13ECh. 0.7 - Prob. 14ECh. 0.7 - Prob. 15ECh. 0.7 - Prob. 16ECh. 0.7 - Prob. 17ECh. 0.7 - Prob. 18ECh. 0.7 - Prob. 19ECh. 0.7 - Prob. 20ECh. 0.7 - Prob. 21ECh. 0.7 - Prob. 22ECh. 0.7 - Prob. 23ECh. 0.7 - Prob. 24ECh. 0.7 - Prob. 25ECh. 0.7 - Prob. 26ECh. 0.7 - Prob. 27ECh. 0.7 - Prob. 28ECh. 0.7 - Prob. 29ECh. 0.7 - Prob. 30ECh. 0.8 - Prob. 1ECh. 0.8 - Prob. 2ECh. 0.8 - Prob. 3ECh. 0.8 - Prob. 4ECh. 0.8 - Prob. 5ECh. 0.8 - Prob. 6ECh. 0.8 - Prob. 7ECh. 0.8 - Prob. 8ECh. 0.8 - Prob. 9ECh. 0.8 - Prob. 10ECh. 0.8 - Prob. 11ECh. 0.8 - Prob. 12ECh. 0.8 - Prob. 13ECh. 0.8 - Prob. 14ECh. 0.8 - Prob. 15ECh. 0.9 - Prob. 1ECh. 0.9 - Prob. 2ECh. 0.9 - Prob. 3ECh. 0.9 - Prob. 4ECh. 0.9 - Prob. 5ECh. 0.9 - Prob. 6ECh. 0.9 - Prob. 7ECh. 0.9 - Prob. 8ECh. 0.9 - Prob. 9ECh. 0.9 - Prob. 10ECh. 0.9 - Prob. 11ECh. 0.9 - Prob. 12ECh. 0.9 - Prob. 13ECh. 0.9 - Prob. 14ECh. 0.9 - Prob. 15ECh. 0.9 - Prob. 16ECh. 0.9 - Prob. 17ECh. 0.9 - Prob. 18ECh. 0.9 - Prob. 19ECh. 0.9 - Prob. 20ECh. 0 - Prob. 1PFGCh. 0 - Prob. 2PFGCh. 0 - Prob. 3PFGCh. 0 - Prob. 4PFGCh. 0 - Prob. 5PFGCh. 0 - Prob. 6PFGCh. 0 - Prob. 7PFGCh. 0 - Prob. 8PFGCh. 0 - Prob. 9PFGCh. 0 - Prob. 10PFGCh. 0 - Prob. 11PFGCh. 0 - Prob. 12PFGCh. 0 - Prob. 13PFGCh. 0 - Prob. 14PFGCh. 0 - Prob. 15PFGCh. 0 - Prob. 16PFGCh. 0 - Prob. 17PFGCh. 0 - Prob. 18PFGCh. 0 - Prob. 19PFGCh. 0 - Prob. 20PFGCh. 0 - Prob. 21PFGCh. 0 - Prob. 22PFGCh. 0 - Prob. 23PFGCh. 0 - Prob. 24PFGCh. 0 - Prob. 25PFGCh. 0 - Prob. 26PFGCh. 0 - Prob. 27PFGCh. 0 - Prob. 28PFGCh. 0 - Prob. 29PFGCh. 0 - Prob. 30PFGCh. 0 - Prob. 31PFGCh. 0 - Prob. 32PFGCh. 0 - Prob. 33PFGCh. 0 - Prob. 34PFGCh. 0 - Prob. 35PFGCh. 0 - Prob. 36PFGCh. 0 - Prob. 37PFGCh. 0 - Prob. 38PFGCh. 0 - Prob. 39PFGCh. 0 - Prob. 40PFGCh. 0 - Prob. 41PFGCh. 0 - Prob. 42PFGCh. 0 - Prob. 43PFGCh. 0 - Prob. 44PFGCh. 0 - Prob. 45PFGCh. 0 - Prob. 46PFGCh. 0 - Prob. 47PFGCh. 0 - Prob. 48PFGCh. 0 - Prob. 49PFGCh. 0 - Prob. 50PFGCh. 0 - Prob. 51PFGCh. 0 - Prob. 52PFGCh. 0 - Prob. 53PFGCh. 0 - Prob. 54PFGCh. 0 - Prob. 55PFGCh. 0 - Prob. 56PFGCh. 0 - Prob. 57PFGCh. 0 - Prob. 58PFGCh. 0 - Prob. 59PFGCh. 0 - Prob. 60PFGCh. 0 - Prob. 61PFGCh. 0 - Prob. 62PFGCh. 0 - Prob. 63PFGCh. 0 - Prob. 1PGCh. 0 - Prob. 2PGCh. 0 - Prob. 3PGCh. 0 - Prob. 4PGCh. 0 - Prob. 5PGCh. 0 - Prob. 6PGCh. 0 - Prob. 7PGCh. 0 - Prob. 8PGCh. 0 - Prob. 9PGCh. 0 - Prob. 10PGCh. 0 - Prob. 11PGCh. 0 - Prob. 12PGCh. 0 - Prob. 13PGCh. 0 - Prob. 14PGCh. 0 - Prob. 15PGCh. 0 - Prob. 16PGCh. 0 - Prob. 17PGCh. 0 - Prob. 18PGCh. 0 - Prob. 19PGCh. 0 - Prob. 20PGCh. 0 - Prob. 21PGCh. 0 - Prob. 22PGCh. 0 - Prob. 23PGCh. 0 - Prob. 24PGCh. 0 - Prob. 25PGCh. 0 - Prob. 26PGCh. 0 - Prob. 27PGCh. 0 - Prob. 28PGCh. 0 - Prob. 29PGCh. 0 - Prob. 30PGCh. 0 - Prob. 31PGCh. 0 - Prob. 32PGCh. 0 - Prob. 33PGCh. 0 - Prob. 34PGCh. 0 - Prob. 35PGCh. 0 - Prob. 36PGCh. 0 - Prob. 37PGCh. 0 - Prob. 38PGCh. 0 - Prob. 39PGCh. 0 - Prob. 40PGCh. 0 - Prob. 41PGCh. 0 - Prob. 42PGCh. 0 - Prob. 43PGCh. 0 - Prob. 44PGCh. 0 - Prob. 45PGCh. 0 - Prob. 46PGCh. 0 - Prob. 47PGCh. 0 - Prob. 48PGCh. 0 - Prob. 49PGCh. 0 - Prob. 50PGCh. 0 - Prob. 51PGCh. 0 - Prob. 52PGCh. 0 - Prob. 53PGCh. 0 - Prob. 54PGCh. 0 - Prob. 55PGCh. 0 - Prob. 56PGCh. 0 - Prob. 57PGCh. 0 - Prob. 58PGCh. 0 - Prob. 59PG
Additional Math Textbook Solutions
Find more solutions based on key concepts
A categorical variable has three categories, with the following frequencies of occurrence: a. Compute the perce...
Basic Business Statistics, Student Value Edition
Piston compression A piston is seated at the top of a cylindrical chamber with radius 5 cm when it starts movin...
Calculus: Early Transcendentals (2nd Edition)
Birth Length The mean birth length for U.S. children born at full term (after 40 weeks) is 52.2 centimeters (ab...
Introductory Statistics
A pair of fair dice is rolled. What is the probability that the second die lands on a higher value than does th...
A First Course in Probability (10th Edition)
Using
Find the limits in Exercises 23–46.
25.
University Calculus: Early Transcendentals (4th Edition)
CHECK POINT 1 Find a counterexample to show that the statement The product of two two-digit numbers is a three-...
Thinking Mathematically (6th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Similar questions
- Find U V . 10 U V T 64° Write your answer as an integer or as a decimal rounded to the nearest tenth. U V = Entregararrow_forwardFind the area of a square whose diagonal is 10arrow_forwardDecomposition geometry: Mary is making a decorative yard space with dimensions as shaded in green (ΔOAB).Mary would like to cover the yard space with artificial turf (plastic grass-like rug). Mary reasoned that she could draw a rectangle around the figure so that the point O was at a vertex of the rectangle and that points A and B were on sides of the rectangle. Then she reasoned that the three smaller triangles resulting could be subtracted from the area of the rectangle. Mary determined that she would need 28 square meters of artificial turf to cover the green shaded yard space pictured exactly.arrow_forward
- 7. 11 m 12.7 m 14 m S V=B₁+ B2(h) 9.5 m 16 m h+s 2 na 62-19 = 37 +, M h² = Bu-29arrow_forwardwhat would a of a interscribed angle be with an arc of 93 degrees and inside abgles of 111 and 98arrow_forwardPlease complete through GeoGebra and present the screenshots of the results. Thanks! (This supports on how to submit it.)arrow_forward
- Door 87.5in to 47 living 44.75 Closet 96in Window ISS.Sin 48in Train Table 96in 48in 132:2 Windowarrow_forward39 Two sides of one triangle are congruent to two sides of a second triangle, and the included angles are supplementary. The area of one triangle is 41. Can the area of the second triangle be found?arrow_forwardA parallelogram with an area of 211.41 m^2 hast a base Thatcher measures 24.3m. Find ist height.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,
Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning
Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
UG/ linear equation in linear algebra; Author: The Gate Academy;https://www.youtube.com/watch?v=aN5ezoOXX5A;License: Standard YouTube License, CC-BY
System of Linear Equations-I; Author: IIT Roorkee July 2018;https://www.youtube.com/watch?v=HOXWRNuH3BE;License: Standard YouTube License, CC-BY