To investigate the effects of a newly discovered inhibitor and enzymology list obtained the resultsshowed in the figure below.Which statement best describes the binding of its inhibitor on the enzyme?~y=0.768r+4.74253-0.568x+4657619....●xXThe inhibitor binds at the active site.The inhibitor binds away from the active site, but after substrate binding.The inhibitor binds away from the active site before or after substrate binding.The inhibitor binds close to the active site, but after substrate binding.The inhibitor binds close to the active site, but prior to substrate binding.red by a strain

Enzymes are highly specialized proteins that have extraordinary catalytic power, greater than that…

Answered: ~0.766+ 47425 y-0.568x46576 . . . . . X…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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am. 206.
A. Which enzyme model involves the enzyme staying the same shape when the substrate binds to it? (lock and key, induced fit) B. If an inhibitor has similiar structure to that of a substrate, does it act as a competitive or noncompetitive inhibitor? C. What is the surface for an active site for an ezyme that binds the substrate to that site?
. The following data, presented by G. Bowes and W. L. Ogre in J. Biol. Chem. (1972) 247:2171–2176, describe the relative rates of incorpo- ration of CO, by rubisco under N, and under pure O,. Decide whether O, is a competitive or uncompetitive inhibitor. [CO,] (mM) Under N2 Under O, 0.20 16.7 10 0.10 12.5 5.6 0.067 8.3 4.2 0.050 7.1 3.2
-Inhibitor +Inhibitor [S] (mM) V0&νβσπ;(μmol/sec). νο&νβσπ: &ν βσπ (μmol/sec) 0.0001 33 17 0.0005 71 50 0.001 83 67 0.005 96 91 0.01 98 95 What is the Vmax of this enzyme WITH iinhibitor?
What enzyme kinetic parameters are apparantly impacted by uncompetitive inhibitors? Vmax Km Both Km and Vmax Neither Km nor Vmax
please make sure the answer you provide is correct i submitted this question differnt times and everytime i got a differnt answer
Please name the differences between competitive and noncompetitive inhibition.
If the allosteric coefficient for ATCase increases from 250 to 1300, the rate of the N-carbamoylaspartate formation: O stays the same and the sigmoidal curve of reaction rate as a function of substrate shifts up. O decreases and the sigmoidal curve of reaction rate as a function of substrate shifts to the left. O increases and the sigmoidal curve of reaction rate as a function of substrate shifts to the left. O stays the same and the sigmoidal curve of reaction rate as a function of substrate shifts to the right. O decreases and the sigmoidal curve of reaction rate as a function of substrate shifts to the right. Question 9 Which of the following CANNOT be targeted for phosphorylation to modulate the activity of an enzyme? O Ser Ala O None of the amino acids listed can be targeted for phosphorylation to modulate enzyme activity The Tyr
(a) You are given the following experimental measurements for the effects of an inhibitor on the initial velocity of an enzymatic reaction. Plot the data and determine what type of inhibition is being observed. Label all axes. [S] (MM) Vo (mM • Vo with I present (mM ⚫s-¹) 1 2.8 3 6.0 1.0 2.5 4 7.0 3.1 8 9.9 12 11.5 4.8 5.7 (b) Briefly explain how varying [S] can be used to determine whether an inhibitor is uncompetitive or competitive. Be sure to include in your explanation why this method would work.
CHEM151/251 Biochemistry 1 a. Determine Km 1. The following data were obtained for a competitive inhibition study in which the [I] = 3 µM for each determination of vo in the presence of inhibitor. The Vmax = 200 μM P/min for both data sets. 200 Vo (UM P/min) 8 8 8 8 8 8 8 8 8 180 160 140 120 100 40 Name (Print)/ID #: the absence of inhibitor. Participation Question # 10 No Inhibitor 50 +Inhibitor 100 [Substrate] (UM) 150 b. Determine Km, app for the data obtained in presence of inhibitor. 200 c. Calculate the value for Ki. Note: a = 1 + [I]/Ki and a¹ = 1 + [I]/Ki*. for the data obtained in
15) The graph at right shows the results of reaction rate vs. substrate concentration for a Michaelis-Menten type enzyme 16) Th a. True b. False* reaction rate substrate concentration
D 1. 0.25 Short answer questions, write answers on blank paper. A plot of enzyme activity with and without an inhibitor present gave the following plot. 0.2 0.15 1/V v in mM/s 0.1 0.05 0 0 0.05 0.1 y=0.67x+0.02 0.15 y=0.2x+0.02 0.2 0.25 0.3 1/[S]. [S] in mM Without the inhibitor, what are the values of Vmax and Km? In the presence of the inhibitor, which of these items has changed and what is (are) the new value(s)? What type of inhibitor is present (explain why you have arrived at this conclusion)? Be sure to include units as necessary--answers that do not contain required units will be marked incorrect

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