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Zinc melts at 420 C (693K) and its standard entropy at 25 C (298 K) is 9.95 cal/deg/mole. Calculate the standard entropy of Zinc at 750 C (1023 K). Given: Heat of Fusion of Zinc at the melting point. AH, = 1.74 kcal/mol CP(693).Zn = 15.35 + 6.40 X 10 x-3T cal/deg/mol CP(1023).Zn = 7.50 cal/deg/mol Si, = Sr,+ T + + $r %3D

Zinc melts at 420 C (693K) and its standard entropy at 25 C (298 K) is 9.95 cal/deg/mole. Calculate the standard entropy of Zinc at 750 C (1023 K). Given: Heat of Fusion of Zinc at the melting point. AH, = 1.74 kcal/mol CP(693).Zn = 15.35 + 6.40 X 10 x-3T cal/deg/mol CP(1023).Zn = 7.50 cal/deg/mol Si, = Sr,+ T + + $r %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1. Zinc melts at 420 C (693K) and its standard entropy at 25 C (298 K) is 9.95 cal/deg/mole. Calculate the standard entropy of Zinc at 750 C (1023 K). Given: Heat of Fusion of Zinc at the melting point. AH, = 1.74 kcal/mol CP(693).Zn = 15.35 + 6.40 X 10 x-3T cal/deg/mol CP(1023).Zn = 7.50 cal/deg/mol S, = S;,+ aT + # + Sar
Transcribed Image Text:1. Zinc melts at 420 C (693K) and its standard entropy at 25 C (298 K) is 9.95 cal/deg/mole. Calculate the standard entropy of Zinc at 750 C (1023 K). Given: Heat of Fusion of Zinc at the melting point. AH, = 1.74 kcal/mol CP(693).Zn = 15.35 + 6.40 X 10 x-3T cal/deg/mol CP(1023).Zn = 7.50 cal/deg/mol S, = S;,+ aT + # + Sar
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