Zinc and sodium metal each react with sulfuric acid according to the following equations.Zn(s)+H2SO4(aq)⟶ZnSO4(aq)+H2(g)Zn(s)+H2SO4(aq)⟶ZnSO4(aq)+H2(g)2Na(s)+H2SO4(aq)⟶Na2SO4(aq)+H2(g)2Na(s)+H2SO4(aq)⟶Na2SO4(aq)+H2(g)A 26.14 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reacted with 264 mL of 1.86 M barium chloride to produce the maximum possible amount of barium sulfate. Determine the percent sodium by mass in the original mixture. 1.)What is the mass percent Na? I just asked this question on here and was told the answer was 12.64, but my homework says that is incorrect. These are the answers that have been wrong so far: 11.9%, 12.3%,16%,53.4%,4.75%,86.4%, and 12.64%. Please help, thanks! **Chemical Reactions with Zinc and Sodium**Zinc and sodium metal each react with sulfuric acid according to the following equations:1. \( \text{Zn(s)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{ZnSO}_4\text{(aq)} + \text{H}_2\text{(g)} \)2. \( 2 \text{Na(s)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Na}_2\text{SO}_4\text{(aq)} + \text{H}_2\text{(g)} \)**Problem Scenario**A 26.14 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reacted with 264 mL of 1.86 M barium chloride to produce the maximum possible amount of barium sulfate. Determine the percent sodium by mass in the original mixture.- **Provided Answer for Mass Percent Na:** 4.75% (This answer is marked as incorrect.)**Additional Calculation**If 82.16 mL of sulfuric acid was added, what was the concentration of the sulfuric acid?- **Provided Answer for Concentration:** 5.96 M (This answer is enclosed in a text box but not marked as incorrect or correct.) **Chemical Reaction and Moles Calculation****Reaction Equation:**\[ \text{Na}_2\text{SO}_4(\text{aq}) + \text{BaCl}_2(\text{aq}) \rightarrow 2\text{NaCl}(\text{aq}) + \text{BaSO}_4(\text{s}) \]**Explanation:**The maximum quantity of barium sulfate (\(\text{BaSO}_4\)) was produced, implying all \(\text{BaCl}_2\) was converted into \(\text{BaSO}_4\). Therefore, the moles of \(\text{BaCl}_2\) equal the moles of \(\text{BaSO}_4\). Use molarity and volume to find moles of barium chloride.**Barium Sulfate Production:**Barium sulfate results from both zinc sulfate and sodium sulfate, with a 1:1 mole ratio. Thus,\[ \text{mol BaSO}_4 = \text{mol ZnSO}_4 + \text{mol Na}_2\text{SO}_4 \]**Mass of Sodium Metal:**To find the mass of sodium, relate zinc sulfate and sodium sulfate amounts to zinc and sodium metals. The balanced chemical reactions indicate:- Zinc produces zinc sulfate in a 1:1 mole ratio.- Sodium produces sodium sulfate in a 2:1 mole ratio.Thus,\[ \text{mol BaSO}_4 = \text{mol Zn} + \frac{1}{2} \text{mol Na} \]**Further Calculations:**Express moles of zinc and sodium in terms of their masses (\(x\) and \(y\)) and their molar masses. Form a second equation to relate \(x\) and \(y\) to the mixture's total mass.

First calculate mole of each Na and Zn then use neutralization reaction to get mass percent. Mass…

Answered: Zinc and sodium metal each react with…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Zinc and sodium metal each react with sulfuric acid according to the following equations.

Zn(s)+H2SO4(aq)⟶ZnSO4(aq)+H2(g)Zn(s)+H2SO4(aq)⟶ZnSO4(aq)+H2(g)

2Na(s)+H2SO4(aq)⟶Na2SO4(aq)+H2(g)2Na(s)+H2SO4(aq)⟶Na2SO4(aq)+H2(g)

A 26.14 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reacted with 264 mL of 1.86 M barium chloride to produce the maximum possible amount of barium sulfate. Determine the percent sodium by mass in the original mixture.

1.)What is the mass percent Na?

I just asked this question on here and was told the answer was 12.64, but my homework says that is incorrect. These are the answers that have been wrong so far: 11.9%, 12.3%,16%,53.4%,4.75%,86.4%, and 12.64%. Please help, thanks!

**Chemical Reactions with Zinc and Sodium**

Zinc and sodium metal each react with sulfuric acid according to the following equations:

1. \( \text{Zn(s)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{ZnSO}_4\text{(aq)} + \text{H}_2\text{(g)} \)

2. \( 2 \text{Na(s)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Na}_2\text{SO}_4\text{(aq)} + \text{H}_2\text{(g)} \)

**Problem Scenario**

A 26.14 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reacted with 264 mL of 1.86 M barium chloride to produce the maximum possible amount of barium sulfate. Determine the percent sodium by mass in the original mixture.

- **Provided Answer for Mass Percent Na:** 4.75% (This answer is marked as incorrect.)

**Additional Calculation**

If 82.16 mL of sulfuric acid was added, what was the concentration of the sulfuric acid?

- **Provided Answer for Concentration:** 5.96 M (This answer is enclosed in a text box but not marked as incorrect or correct.)

**Chemical Reaction and Moles Calculation**

**Reaction Equation:**
\[ \text{Na}_2\text{SO}_4(\text{aq}) + \text{BaCl}_2(\text{aq}) \rightarrow 2\text{NaCl}(\text{aq}) + \text{BaSO}_4(\text{s}) \]

**Explanation:**
The maximum quantity of barium sulfate (\(\text{BaSO}_4\)) was produced, implying all \(\text{BaCl}_2\) was converted into \(\text{BaSO}_4\). Therefore, the moles of \(\text{BaCl}_2\) equal the moles of \(\text{BaSO}_4\). Use molarity and volume to find moles of barium chloride.

**Barium Sulfate Production:**
Barium sulfate results from both zinc sulfate and sodium sulfate, with a 1:1 mole ratio. Thus,

\[ \text{mol BaSO}_4 = \text{mol ZnSO}_4 + \text{mol Na}_2\text{SO}_4 \]

**Mass of Sodium Metal:**
To find the mass of sodium, relate zinc sulfate and sodium sulfate amounts to zinc and sodium metals. The balanced chemical reactions indicate:

- Zinc produces zinc sulfate in a 1:1 mole ratio.
- Sodium produces sodium sulfate in a 2:1 mole ratio.

Thus,

\[ \text{mol BaSO}_4 = \text{mol Zn} + \frac{1}{2} \text{mol Na} \]

**Further Calculations:**
Express moles of zinc and sodium in terms of their masses (\(x\) and \(y\)) and their molar masses. Form a second equation to relate \(x\) and \(y\) to the mixture's total mass.

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