Your read a study in which the researcher reports: Students were randomly assigned to an exercise group or a video group. After 45 minutes of activity, students completed an attention test. Attention was significantly higher in the exercise group (M = 17.50, SD = 3.50) than in the video group (M = 12.00, SD = 7.50), t(68) = 3.12, p < .05.Although you may not understand everything in this report, you do know that: a.As measured by the median, attention was higher in the exercise group than the video group. b.In the exercise group, attention scores fell an approximate average of 3.50 units from the mean of 17.50.c.Attention was more varied in the exercise group than the video group.d.In the video group, we would expect to see most attention scores falling between 12 & 19.50 (i.e., M + 1SD)

Name: Your read a study in which the researcher reports: Students were ra
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Your read a study in which the researcher reports: Students were randomly assigned to an exercise group or a video group. After 45 minutes of activity, students completed an attention test. Attention was significantly higher in the exercise group

Answered: Your read a study in which the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Topic Video

Question

Your read a study in which the researcher reports: Students were randomly assigned to an exercise group or a video group. After 45 minutes of activity, students completed an attention test. Attention was significantly higher in the exercise group (M = 17.50, SD = 3.50) than in the video group (M = 12.00, SD = 7.50), t(68) = 3.12, p < .05.

Although you may not understand everything in this report, you do know that:

As measured by the median, attention was higher in the exercise group than the video group.

In the exercise group, attention scores fell an approximate average of 3.50 units from the mean of 17.50.

Attention was more varied in the exercise group than the video group.

In the video group, we would expect to see most attention scores falling between 12 & 19.50 (i.e., M + 1SD)

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

Expert Solution

Step 1

Given
The mean attention score for exercise group $M = 17.50$
The standard deviation for attention score for exercise group $S D = 3.50$

The mean attention score for video group $M = 12$
The standard deviation for attention score for video group $S D = 7.50$

The standard deviation is a measure of spread of the data distribution and it tell us the average amount of variability in the data distribution, which is nothing but how many average units the data point's are away from its mean.

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions