Your manager asked you to explain the difference between three-point bending test and four-point bending test by using a standard specimen each one has the following dimensions: 1. Force = 30 KN. 2. Thickness= 5 cm. 3. Width = 10 cm. 4. Length = 25 cm. Calculate the stress on each specimen then justify your answer

Your manager asked you to explain the difference between three-point bending test and four-point bending test by using a standard specimen each one has the following dimensions: 1. Force = 30 KN. 2. Thickness= 5 cm. 3. Width = 10 cm. 4. Length = 25 cm. Calculate the stress on each specimen then justify your answer

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.5P: The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen...

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A tension test was performed on a specimen having an original diameter of 12.76 mm and a gage length of 56.97 mm.The data are listed in the table. Plot the stress-strain diagram, and determine approximately the modulus of elasticity, the ultimate stress, and the fracture stress. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Redraw the linear-elastic region, using the same stress scale but a strain scale of 20 mm = 0.001 mm/mm. Also, determine the 0.2% yield stress.
The tensile test was conducted on a specimen with a diameter of 0.5 inch. A strain gage was bonded to the specimen so that the strain could be obtained directly. The following data were obtained. a) create a table of stress and strain values. Plot this data points and draw the best fit straight line through them. b) what is the slope of this line? What does this value represent?
1.5-5 A tension test was conducted on a specimen with a circular cross section of diameter 0.5 inch and a gage length of 8 inches. (The gage length is the distance between two marks on the specimen. The deformation is measured within this length.) The stress and strain were computed from the test data and plotted. Two plots are shown here; the first one shows the entire test range, and the second shows a portion near the pro- portional limit. a. Draw best-fit lines to obtain stress-strain curves. b. Estimate the proportional limit. c. Use the slope of the best-fit line to estimate the modulus of elasticity. Stress (ksi) Stress (ksi) 80 70 60 50 40 30 20 10 0 60 50 40 30 20 10 0 → 0 0 0.05 0.002 0.1 0.004 0.15 Strain 0.006 Strain FIGURE P1.5-5 0.2 0.008 0.25 0.01 0.3 0.012
1.5-5 A tension test was conducted on a specimen with a circular cross section of diameter 0.5 inch and a gage length of 8 inches. (The gage length is the distance between two marks on the specimen. The deformation is measured within this length.) The stress and strain were computed from the test data and plotted. Two plots are shown here; the first one shows the entire test range, and the second shows a portion near the pro- portional limit. d. Estimate the 0.2% offset yield strength. e. Estimate the ultimate stress. f. If a load of 10 kips is applied and then removed, estimate the permanent defor- mation in inches. Stress (ksi) Stress (ksi) 80 70 60 50 40 30 20 10 0 60 50 40 30 20 10 0 0 0 0.05 0.002 0.1 0.004 0.15 Strain 0.006 Strain FIGURE P1.5-5 0.2 0.008 0.25 0.01 0.3 0.012
The nominal stress-strain diagram for a specimen having an original diameter of 10 mm and a gauge length of 50 mm is shown below. Using the given nominal stress-nominal strain diagram, answer this question. The inset shows a detailed view of the curve at low strains. 400 350 300 250 Stress (MPa) 200 150 100 50 0 0.00 Stress (MPa) 350 kN 300 250 200 150 100 50 0 0.000 0.002 0.004 0.006 0.008 0.010 0.012 Strain 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 Strain 0.18 What is the maximum force that could be applied to the specimen before it plastically deforms?
A tension test is being conducted on a steel-rod specimen with a gauge length of L0=50mm and initial diameter of d0=13mm. Data were collected to form the conventional stress-strain diagram as shown. From the diagram, f = 510 MPa , e = 693 MPa , g = 565 MPa , and ℎ = 0.15 mm/mm Assuming that the strain remains constant throughout the region between the gauge points, determine the nominal strain ε experienced by the rod if it is elongated to L = 65.0 mm.
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A tension test is being conducted on a steel-rod specimen with a gauge length of L0=2 in and initial diameter of d0=0.5 in. Data were collected to form the conventional stress-strain diagram as shown. From the diagram, f = 74.0 ksi, e = 104.0 ksi , g = 85.0 ksi , and h = 0.15 in/in. Assuming that the strain remains constant throughout the region between the gauge points, determine the nominal strain ε experienced by the rod if it is elongated to L = 2.7 in . Assuming that the stress is constant over the cross-sectional area and if the tension force used is P = 11.0 kips, find the nominal stress experienced by the rod. Determine the force P needed to reach the ultimate stress in the steel-rod specimen.
The following uniaxial tensile testing data were collected from a ductile cast iron test specimen of initial diameter Do= 20.0 mm and initial length lo=40.0 mm. After fracture the total specimen length was lf= 47.42 mm and the specimen diameter was Df = 18.35 mm. engineering stress-strain plot, including the expanded inset figure and the numerical values shown in Table 1, all shown on the next page, determine the following: 1) the modulus of elasticity E 2) the 0.2% offset yield strength 3) the tensile strength Using the data given in the 4) the maximum load that can be sustained by the specimen 5) the specimen length when plastic deformation started to occur Stress Strain Curve Table 1. Strain Stress [MPa] 450 400 0.000463 79.57 0.000925 159.16 350 350 300 0.001388 238.74 300 250 0.005 286.49 250 200 0.015 334.23 150 0.039 381.98 200 0.1 416.99 100 150 0.188 397.89 50 100 0.002 0.004 0.006 0.008 0.01 Strain s 50 0.05 0.1 0.15 0.2 Strain ɛ Stress o [MPa] Stress o [MPa]
I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compute the compressive stress for the respective ages of the specimen. The diameter of the specimens is 150mm and the height is 300mm. Load (N) 176,000 Stress (MPa) Age 7days 14 days 28 days 252,000 340,000 2. Compute the tensile stress from the value acquired from the experiment if the breaking load is 105KN. The diameter of the specimen is 150mm and the height is 300mm. 3. Compute the flexural stress of the sample specimen if its dimension is 150mm x 150mm x 500mm in a 3 point loading. The effective length is 400mm. The specimen failed at 44,300N in the middle third. 4. Compression test was applied to a certain type of wood. Compute the stress based on the following dimensions. The grains are parallel with the length. а. Dimension (mm) Load (N) Compressive stress (МРа) Compression Test
A hot rolled steel tension test sample has a diameter of 6 mm and the original gage length of 30 mm. In a test to fracture, the stress and strain data below were obtained. Determine Generic Strain Value, %0.2 offset strain, and Calculated stress at %0.2 offset. Original diameter - 6mm Original Length - 30 mm Fracture diameter - 4.54 mm
The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3⁄8 inch and the gage length (the length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress–strain data and draw a best-fit curve. c. Compute the modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress