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You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density Consider the following: you mix 8.40 ml of CHCl (d-1.492 g/ml) and 8.10 ml of CHIBr; (d-2.890 g/ml), giving 16.5 ml of solution. What is the density of this mixture? Density-2.183 g/mL Suppose now that you wanted to determine the density of a small crystal to confirm that it is sulfur. From the literature, you know that sulfur has a density of 2.07 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CECI, (d-1.492 g/ml) and CHBr, (d-2.890 g/ml)? (Note: 1 mL-11 V(CHCL,)- V(CHBrs)- ML

You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density Consider the following: you mix 8.40 ml of CHCl (d-1.492 g/ml) and 8.10 ml of CHIBr; (d-2.890 g/ml), giving 16.5 ml of solution. What is the density of this mixture? Density-2.183 g/mL Suppose now that you wanted to determine the density of a small crystal to confirm that it is sulfur. From the literature, you know that sulfur has a density of 2.07 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CECI, (d-1.492 g/ml) and CHBr, (d-2.890 g/ml)? (Note: 1 mL-11 V(CHCL,)- V(CHBrs)- ML

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density. Consider the following: you mix 8.40 mL of CHCl (d-1.492 g/mL) and 8.10 mL of CHIBr; (d-2.890 g/mL), giving 16.5 ml. of solution. What is the density of this mixture? Density-2.183✔ g/m² Suppose now that you wanted to determine the density of a small crystal to confirm that it is sulfur. From the Mterature, you know that sulfur has a density of 2.07 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCI, (d 1.492 g/mL) and CHBr, (d-2.890 g/ml)? (Note: 1 mL-1 cm²) V(CHCl₂)= V(CHB)- mL ml
Transcribed Image Text:You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density. Consider the following: you mix 8.40 mL of CHCl (d-1.492 g/mL) and 8.10 mL of CHIBr; (d-2.890 g/mL), giving 16.5 ml. of solution. What is the density of this mixture? Density-2.183✔ g/m² Suppose now that you wanted to determine the density of a small crystal to confirm that it is sulfur. From the Mterature, you know that sulfur has a density of 2.07 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCI, (d 1.492 g/mL) and CHBr, (d-2.890 g/ml)? (Note: 1 mL-1 cm²) V(CHCl₂)= V(CHB)- mL ml
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