You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density. Consider the following: you mix 5.50 mL of CHCL3 ( d= 1.492 g/mL) and 6.40 mL of CHBr3 (d = 2.890 g/mL), giving 11.9 mL of solution. What is the density of this mixture?

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You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density.

 

Consider the following: you mix 5.50 mL of CHCL3 ( d= 1.492 g/mL) and 6.40 mL of  CHBr3 (d = 2.890 g/mL), giving 11.9 mL of solution. What is the density of this mixture?

Expert Solution
Step 1

Given, volume of CHCl3 = 5.50 mL

           density of CHCl3 = 1.492 g/mL

           volume of CHBr3 = 6.40 mL

           density of CHBr3 = 2.890 g/mL

          total volume of solution mixture = 11.9

 

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