The radius of cesium atom, Cs, 1s 265 pm, and its mass is 2.21 x 10 22 g. What is the density of the atom in grams per cubic centimeter (g/cm')? Assume the nucleus is a sphere with volume, V = 3. (1 pm = 1×10-12 m).

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**Educational Website Transcription:**

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### Homework Problems:

**3. The radius of cesium atom, Cs, is 265 pm, and its mass is 2.21 × 10<sup>−22</sup> g. What is the density of the atom in grams per cubic centimeter (g/cm³)? Assume the nucleus is a sphere with volume, V = (4/3)πr³. (1 pm = 1×10<sup>−12</sup> m).**

**4. The density of pure lead is 11.34 g/cm³ at 20 °C. If 7.80 g of pure lead pellets is added to a graduated cylinder containing 15.3 mL of water, to what volume level will the water in the cylinder rise?**

**5. An iron wire (density = 7.87 g/cm³) has a diameter of 0.50 mm. If a sample of this iron wire has a mass of 24 g, how long is this wire in meters? (Cylinder volume, V = πr²l).**

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**Additional Details for Homework Problems:**

**Problem 3: Understanding Density Calculation for a Cesium Atom**
In problem 3, you need to first convert the given radius from picometers to meters and then calculate the volume of the cesium atom assuming it's a sphere using the formula V = (4/3)πr³. Subsequently, you can calculate the density by dividing the atom's mass by its volume and converting the units to grams per cubic centimeter.

**Problem 4: Volume Displacement by Lead Pellets**
In problem 4, using the density of lead, compute the volume of the lead pellets added to the water. Since density is mass per unit volume, the volume displaced can be found by dividing the mass of the pellets by the density of lead. The final volume level in the graduated cylinder is the initial volume of water plus the volume displaced by the lead.

**Problem 5: Determining the Length of an Iron Wire**
For problem 5, with the density and diameter of the wire known, you should first find the volume of the wire using mass and density. Knowing the volume, use the formula for the volume of a cylinder (V = πr²l) to solve for the length (l) of the wire, converting the units appropriately to get the answer in meters.

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Transcribed Image Text:**Educational Website Transcription:** --- ### Homework Problems: **3. The radius of cesium atom, Cs, is 265 pm, and its mass is 2.21 × 10<sup>−22</sup> g. What is the density of the atom in grams per cubic centimeter (g/cm³)? Assume the nucleus is a sphere with volume, V = (4/3)πr³. (1 pm = 1×10<sup>−12</sup> m).** **4. The density of pure lead is 11.34 g/cm³ at 20 °C. If 7.80 g of pure lead pellets is added to a graduated cylinder containing 15.3 mL of water, to what volume level will the water in the cylinder rise?** **5. An iron wire (density = 7.87 g/cm³) has a diameter of 0.50 mm. If a sample of this iron wire has a mass of 24 g, how long is this wire in meters? (Cylinder volume, V = πr²l).** --- **Additional Details for Homework Problems:** **Problem 3: Understanding Density Calculation for a Cesium Atom** In problem 3, you need to first convert the given radius from picometers to meters and then calculate the volume of the cesium atom assuming it's a sphere using the formula V = (4/3)πr³. Subsequently, you can calculate the density by dividing the atom's mass by its volume and converting the units to grams per cubic centimeter. **Problem 4: Volume Displacement by Lead Pellets** In problem 4, using the density of lead, compute the volume of the lead pellets added to the water. Since density is mass per unit volume, the volume displaced can be found by dividing the mass of the pellets by the density of lead. The final volume level in the graduated cylinder is the initial volume of water plus the volume displaced by the lead. **Problem 5: Determining the Length of an Iron Wire** For problem 5, with the density and diameter of the wire known, you should first find the volume of the wire using mass and density. Knowing the volume, use the formula for the volume of a cylinder (V = πr²l) to solve for the length (l) of the wire, converting the units appropriately to get the answer in meters. --- Note: This
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