You learn your effluent has 50 mg VSS/L. Your boss wants to know how this affects other effluent quality parameters. Estimate the oxygen demand of this material and the contribution to the effluent total nitrogen concentration (show calculations).
You learn your effluent has 50 mg VSS/L. Your boss wants to know how this affects other effluent quality parameters. Estimate the oxygen demand of this material and the contribution to the effluent total nitrogen concentration (show calculations).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![You learn your effluent has 50 mg VSS/L. Your boss wants to know how this affects other effluent
quality parameters. Estimate the oxygen demand of this material and the contribution to the effluent
total nitrogen concentration (show calculations).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F354f0f07-4e58-4740-9109-f710361ed65f%2Ff70679ed-5add-49a4-924b-0b5280255ad3%2F502xmxn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You learn your effluent has 50 mg VSS/L. Your boss wants to know how this affects other effluent
quality parameters. Estimate the oxygen demand of this material and the contribution to the effluent
total nitrogen concentration (show calculations).
![12:07 &
3 ull 78%
Possibly useful info
eeq/mole
cells
Nitrogen Source
AGpe (kJ/g
cells)
3.33
AGpe (kJ/eeq
cells)
Ammonium (NH,")
Nitrate (NO;)
Nitrite (NO2")
Dinitrogen (N2)
20
18.8
28
3.33
13.5
26
3.33
14.5
23
3.33
16.4
R = fe Re + f, Rs
R = fe (Ra – Rd) + fs (Rc – Rd)
So
R = fe Ra + fs Rc – Rd
(Note that -Rd denotes that the direction of the reaction is the
opposite of that reported in the Rittmann/McCarty tables) Also note
that if the direction of a reaction is reversed, the sign on the free
energy value also changes).
Chemical
AGf
(kJ/mol)
species
AG, AG,
A =-
OH-
-198.76
ɛAG,
Toluene
n=-1if AG, <0
+114.22
(C,H3)
n=1if AG, >0
Water
-237
1
H+
-39.9
1+ A
N2
f +f° =1
Carbon
AG, = 35.09 – AG.°
Dioxide
-394
(CO2)
ɛ = 0.6
Nitrate
-111.34
(NO3)
Molecular Weights
Oxygen 16
Hydrogen 1
Nitrogen 14
Carbon 12
ΔG"ΣΔG, Products-ΣΔG, Reactants
= [(c) (AG; of C) + (d) (AG; of D)] – [(a) (AG; of A) + (b) (AG¡ of B)]
Sulfur 32
AG' = AG" + RT In [C][D]d
where: Ris the ideal gas constant 0.00829 kJ/mol-ºK
[A]°[B]»
Tis the absolute temperature (°K) and °K = °C + 273.15
[In this equation, [] represents the activity of the constituent. The activity of the solutes (aqueous
species) is close enough for our purposes to molar (M) concentration. The activity of gaseous
species (e.g. H2, O2, CO2), are entered as partial pressures in atmospheres (atm). The solvent
(typically water in our applications) is considered to have an activity of 1.]
$3,29344
Comp sci.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F354f0f07-4e58-4740-9109-f710361ed65f%2Ff70679ed-5add-49a4-924b-0b5280255ad3%2Fgj3ciw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12:07 &
3 ull 78%
Possibly useful info
eeq/mole
cells
Nitrogen Source
AGpe (kJ/g
cells)
3.33
AGpe (kJ/eeq
cells)
Ammonium (NH,")
Nitrate (NO;)
Nitrite (NO2")
Dinitrogen (N2)
20
18.8
28
3.33
13.5
26
3.33
14.5
23
3.33
16.4
R = fe Re + f, Rs
R = fe (Ra – Rd) + fs (Rc – Rd)
So
R = fe Ra + fs Rc – Rd
(Note that -Rd denotes that the direction of the reaction is the
opposite of that reported in the Rittmann/McCarty tables) Also note
that if the direction of a reaction is reversed, the sign on the free
energy value also changes).
Chemical
AGf
(kJ/mol)
species
AG, AG,
A =-
OH-
-198.76
ɛAG,
Toluene
n=-1if AG, <0
+114.22
(C,H3)
n=1if AG, >0
Water
-237
1
H+
-39.9
1+ A
N2
f +f° =1
Carbon
AG, = 35.09 – AG.°
Dioxide
-394
(CO2)
ɛ = 0.6
Nitrate
-111.34
(NO3)
Molecular Weights
Oxygen 16
Hydrogen 1
Nitrogen 14
Carbon 12
ΔG"ΣΔG, Products-ΣΔG, Reactants
= [(c) (AG; of C) + (d) (AG; of D)] – [(a) (AG; of A) + (b) (AG¡ of B)]
Sulfur 32
AG' = AG" + RT In [C][D]d
where: Ris the ideal gas constant 0.00829 kJ/mol-ºK
[A]°[B]»
Tis the absolute temperature (°K) and °K = °C + 273.15
[In this equation, [] represents the activity of the constituent. The activity of the solutes (aqueous
species) is close enough for our purposes to molar (M) concentration. The activity of gaseous
species (e.g. H2, O2, CO2), are entered as partial pressures in atmospheres (atm). The solvent
(typically water in our applications) is considered to have an activity of 1.]
$3,29344
Comp sci.
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