Pretend that you are conducting this experiment in the laboratory and answer the following questions. You are asked to weigh 2 g of lithium and add it to 1500 ml of distilled water +2 drops of indicator, knowing that the density of water is 1 at room temperature while conducting this experiment. After knowing the amount of LiOH, you need to dilute to prepare 0.025 M of LiOH in a 3000 ml(v) solution. Show your calculation and units.Knowing that the initial volume that you used was 1500 ml(v). Use this equation to calculate ( CLiOH x VLiOH) before dilution = (CLiOH x VLiOH) after dilution
Pretend that you are conducting this experiment in the laboratory and answer the following questions. You are asked to weigh 2 g of lithium and add it to 1500 ml of distilled water +2 drops of indicator, knowing that the density of water is 1 at room temperature while conducting this experiment. After knowing the amount of LiOH, you need to dilute to prepare 0.025 M of LiOH in a 3000 ml(v) solution. Show your calculation and units.Knowing that the initial volume that you used was 1500 ml(v). Use this equation to calculate ( CLiOH x VLiOH) before dilution = (CLiOH x VLiOH) after dilution
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Pretend that you are conducting this experiment in the laboratory and answer the following questions.
You are asked to weigh 2 g of lithium and add it to 1500 ml of distilled water +2 drops of indicator, knowing that the density of water is 1 at room temperature while conducting this experiment.
After knowing the amount of LiOH, you need to dilute to prepare 0.025 M of LiOH in a 3000 ml(v) solution. Show your calculation and units.Knowing that the initial volume that you used was 1500 ml(v).
Use this equation to calculate ( CLiOH x VLiOH) before dilution =
(CLiOH x VLiOH) after dilution
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