You cross a true breeding, yellow-bodied, male fruit fly to a true breeding, wild-type, female fly and observe that all the progeny have a wild- type body colour. If you set the reciprocal cross, you notice that all the female flies have a wild-type body colour and that all the male flies have yellow bodies. What can you conclude regarding the gene that determines body colour (yellow) in Drosophila? Select one: O a. The yellow gene assorts independently. cross out O b. A mutant yellow gene is lethal. cross out O c. Nothing can be concluded regarding the gene that determines body colour in Drosophila. cross out O d. The yellow gene is sex-linked. cross out O e. The yellow gene is linked to the centromere. cross out

You cross a true breeding, yellow-bodied, male fruit fly to a true breeding, wild-type, female fly and observe that all the progeny have a wild- type body colour. If you set the reciprocal cross, you notice that all the female flies have a wild-type body colour and that all the male flies have yellow bodies. What can you conclude regarding the gene that determines body colour (yellow) in Drosophila? Select one: O a. The yellow gene assorts independently. cross out O b. A mutant yellow gene is lethal. cross out O c. Nothing can be concluded regarding the gene that determines body colour in Drosophila. cross out O d. The yellow gene is sex-linked. cross out O e. The yellow gene is linked to the centromere. cross out

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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In a certain plant, the dominant form of gene B codes for blue fruit, while the recessive form results in pink fruit. The dominant form of another gene, E, inhibits the activity of the enzyme coded for by gene B, resulting in white fruit, while the recessive form is unable to inhibit this enzyme and results in colored (i.e., blue or pink) fruit. A doubly-homozygous dominant white-fruited plant is crossed with a pink-fruited plant. The F1 progeny were then self-crossed to generate the F2 generation. Determine the ratios of genotypes and phenotypes for each generation.
In Drosophila, males from a true-breeding stock with raspberry-colored eyes were mated to females from a true-breeding stock with sable-colored bodies. In the F1 generation, all the females had wild-type eye and body color, while all the males had wild-type eye color but sable-colored bodies. When F1 males and females were mated to each other, the F2 was composed of: 216 females with wild-type eyes and wild-type bodies 223 females with wild-type eyes and sable bodies 191 males with wild-type eyes and sable bodies 188 males with raspberry eyes and wild-type bodies 23 males with wild-type eyes and bodies 27 males with raspberry eyes and sable bodies Which statements are consistent with the above data? (Select all correct answers.) The alleles causing the raspberry-colored eye and sable-colored body phenotypes are dominant to the corresponding wild-type alleles The genes controlling raspberry-colored eyes and sable-colored bodies map…
In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cM
You are doing a cross with Drosophila using the following two traits. Curly wings is dominant over straight wings, and round eyes is dominant over elliptical eyes. You cross a female fly that is known to be heterozygous for both genes with a male that is heterozygous for the wing gene but has elliptical eyes. This cross produces 74 flies with curly wings and round eyes, 61 with curly wings and elliptical eyes, 24 with straight wings and round eyes, and 21 with straight wing and elliptical eyes. Calculate the expected phenotype ratios for this cross, then use the chi-square test to see if the observed data are consistent with the expected numbers.
In dogs, black coat color (B) is dominant to yellow coat color (b), and straight fur (C) is dominant to curly fur (c). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex-linked. In a cross between two BbCc parents, predict the fraction of offspring with black coat color and straight fur. Give two digits after decimals.
What are the F1 phenotypes expected from a cross between a heterozygous red-eyed female fruit fly (XWXw) and a hemizygous red-eyed male fruit fly (XWY)? half of the F1 males will have white eyes, and all F1 females will have red eyes half of the F1 females will have white eyes, and half of the F1 males will have red eyes all F1 males will have white eyes, and all F1 females will have red eyes all F1 males will have white eyes, and all F1 females will have white eyes all F1 progeny will have red eyes
In Drosophila, the allele for long legs (sl*) is wild-type and the allele for short legs (sl) is mutant. The allele for gray body color (b*) is wild-type and the allele for black body color (b') is mutant. The loci for leg length and body color are linked. Flies with sl*sl* b*b* genotypes are mated with flies that have sl s bb genotypes. A testcross was then performed in which the F, offspring with sl*sl b*b genotypes were mated with flies with sl sl. b'b genotypes. The phenotypes of 1000 offspring were recorded. There were 470 flies with long legs and grey body, 30 flies with long legs and black body, 30 flies with short legs and grey body, and 470 flies with short legs and black body. Which of these phenotypes are parental phenotypes? VWhich of these phenotypes are recombinant phenotypes? What is the distance between these two gene loci in centiMorgans (map units)?
Suppose researchers identified two Drosophila melanogaster mutant phenotypes. One phenotype is called maniac and the other is called shiny. In order to determine the mode of inheritance of the mutant allele responsible for each phenotype, males that have both mutant phenotypes are mated with wild-type (wt) females to produce F₁ progeny. Then, the F₁ progeny are mated together and the F2 progeny are scored. F₁ phenotypic class maniac male maniac female n 481 478 autosomal dominant for maniac and X-linked dominant for shiny autosomal recessive for maniac and autosomal recessive for shiny autosomal dominant for maniac and X-linked recessive for shiny X-linked dominant for maniac and X-linked recessive for shiny What is the genotype of the original male parent? F2 phenotypic class maniac female maniac male What is the mode of inheritance for the genes controlling maniac and shiny? maniac, shiny male shiny male wt female wt male homozygous mutant at both loci heterozygous mutant at one…
In the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosis
In DrosophilaI, yellow body (y), crossveinless (cv), and forked bristles (f) are all found in the X chromosome, in that order. Yellow is 14 map units from crossveinless, and crossveinlessis 32 map units from forked. A yellow, forked female is crossed to a crossveinless male. An F1 female is crossed to a yelow, crossveinless, forked male, yielding the F2 generation. In the F2, what is the probability of obtaining progeny that express crossveinless and forked, but not yellow? Assume a coefficient of coincidence of 1. In the F2, what is the probability of obtaining progeny that are completely wild type? In the F2, what is the probability of obtaining progeny that express crossveinless, but not yellow or forked?