In the fruit fly *Drosophila*, there is a dominant gene for gray body and its recessive allele for black body. At another gene locus, there is a dominant gene for normal wings and its recessive allele for vestigial wings. A female that is heterozygous at both gene loci was mated with a male that is homozygous for both recessive alleles, and the following results were observed among the offspring:- Black body and vestigial wings: 370- Black body and normal wings: 130- Gray body and vestigial wings: 120- Gray body and normal wings: 380Knowing this, complete the sentences with the correct terms:Options:- 37%- 25%- On the same chromosome- 75cM- 75%- On different chromosomes- 25cM- 13%- 38%1. Based on the results of this cross, these two gene loci are probably located ______________.2. The percentage of recombinant types observed among the offspring is ______________.3. The percentage of parental types observed among the offspring is ______________.4. The distance between these two gene loci is ______________.The exercise involves completing these sentences by analyzing the genetic results and determining linkage.

Crossing over is common during meiosis, but crossing over between very close genes is rare because they usually inherit together because they are so close. If crossing over occurs between very close genes, which is a rare event, recombination frequency is a good measure to measure the distance between the two genes. offsprings Normalparentral type ⇒ b vg b vg (black vestigial) = 370 b+ vg+b+ vg+ (gray normal) = 380 Recombinent type = b vg+ b vg+ (black normal)= 130 b+ vg b+ vg (gray vestigial) = 120 Total offsprings = 370 +380 + 130 +120 = 1000 parentral type = 370 +380 =750 = 75% recombinent type = 130 +120 = 250 = 25% Thus distance b/w two genes аrе 25 mар unit Based on the results of this cross, these two gene loci are probably located = on the same chromosome The percentage of recombinant types observed among the offspring is= 75% The percentage of parental types observed among the offspring is= 25%