You carefully weigh out 17.00 g g of CaCO 3  CaCO3 powder and add it to 68.85 g g of HCl HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 78.88 g g . The relevant equation is CaCO 3 (s)+2HCl(aq)→H 2 O(l)+CO 2 (g)+CaCl 2 (aq) CaCO3(s)+2HCl(aq)→H2O(l)+CO2(g)+CaCl2(aq) Assuming no other reactions take place, what mass of CO 2  CO2 was produced in this reaction?

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You carefully weigh out 17.00 g g of CaCO 3  CaCO3 powder and add it to 68.85 g g of HCl HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 78.88 g g . The relevant equation is

CaCO 3 (s)+2HCl(aq)→H 2 O(l)+CO 2 (g)+CaCl 2 (aq) CaCO3(s)+2HCl(aq)→H2O(l)+CO2(g)+CaCl2(aq)

Assuming no other reactions take place, what mass of CO 2  CO2 was produced in this reaction?

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CaCO3 (s) + 2 HCL (aq)  H2O (l)+ CO2(g) + CsCl2 (aq)Thus from 1 mol of CaCO3 (s) , 1 mol of CO2(g) is formedMolecular weight of CaCO3 = (40+12+16×3)g = 100g Molecular weight of CO2 = (12+2×16)g = 44 gThus from 100g of CaCO3 (s), 44g of CO2 is fprmedThus from 17g of CaCO3 , CO2 is produced                                                     =44 g100 g×17g                                                     = 7.48 g

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