You are given the null and alternative hypotheses and the sample information shown below. Complete parts a and b below.Sample 1n1 = 120S, = 34X = 130Sample 2n2 = 135HA: H1- H2#0S2 = 36X2 = 150a. Develop the appropriate decision rule, assuming a significance level of 0.01 is to be used.Select the correct choice below and fill in the answer box(es) to complete your choice.(Round to two decimal places as needed.)O A. Reject Họ if t<or t>O B. Reject Họ if t>O C. Reject H, if t<b. Test the null hypothesis and indicate whether the sample information leads you to reject or fail to reject the null hypothesis. Use the test statistic approach.Calculate the value of the test statistic.t=(Round to two decimal places as needed.)Since the test statisticV in the rejection region,the null hypothesis. There isV evidence at a = 0.01 to conclude that the two population meansare different.

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Answered: You are given the null and alternative…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the data below to test the claim that the weight loss was greater with the low fat diet compared to the low carbohydrate diet. Use a 10% level of significance. Low Fat Low Carbohydrate x¯1=3.7lbs 1=5.2lb n1=57 x¯1=2.7 lbs1=4.9lb n1=62 Identify the tail of the test. What is the P-value? Will the null hypothesis be rejected? Is the initial claim supported?
Show your complete solution II. Use an appropriate statistical tool to test the hypothesis. Use the stepwise method of hypothesis testing. 2. An experimenter was interested in the effect of sleep deprivation on the ability to detect moving objects on a radar screen. The 20 subjects were randomly assigned to one of 4 different conditions (0, 12, 24, 36 hours without sleep). Recorded is the number of failures in spotting moving objects during a test period. Conduct the appropriate test using an alpha of .05. O hrs 12 hrs 24 hrs 36 hrs 36 38 46 76 45 66 20 46 67 62 26 22 61 44 21 40 59 61 74 21
Suppose that you have to decide if the mean of the light bulbs last longer than 150 hours. You choose a random sample of 14 bulbs of each brand. What decision should you make at the 5% significance level (alpha = 0.05)? 128 189 139 148 186 141 163 101 195 142 174 114 196 191 a. z = -2.576 b. t = +1.796 c. t = + 1.771 d. z = + 1.796
Two samples with P, =.25,n, = 36 and p, = .3,n, = 49. Test if populations p, # p, at a= 0.05 level of significance. 8 %3D
Test the claim about the population mean, at the given level of significance using the given sample statistics. Claim 50, a0.04, 351. Sample statistics i 48 2, n- 72 Identily the null and alternative hypotheses. Choose the corect answer below OA. H: p 50 H, p50 OB. H: 50 H, pe50 OC. Họ p> 50 D. H 50 H, 50 OE Ho 50 H, 50 OF. H: p= 50 Calculate the standardized test statistic The standardized test statistic is -4.35. (Round to two decimal places as needed) Determine the critical value(s) Select the corect choice below and flin the answer box to complete your cholce. (Round to two decimal places as needed) OA. The critical value is O B. The critical values are
After clicking the Generate Results button, SALT will display the summary of the One Sample t test on the right side of the Inferential Statistics page. Enter the requested values below. Round your standard error to three decimal places and your test statistic to two decimal places. Standard Error: Test Statistic: Degrees of freedom: P-value: 0.493 66.366 53 53 less than 0.05 0.493 66.37 less than 0.05 Step 5 of 5 Since the P-value is less than our significance value of 0.05, this leads us to reject the null hypothesis. Based on the sample data, there ---Select--- convincing evidence that male Boston Marathon winners have an average finish time that is longer than the male Boston Wheelchair Marathon winners than what could have resulted from sampling error alone. In other words, Boston's male wheelchair athlete winners finish a marathon in ---Select--- time, on average, than male Boston marathon winners. Optional extension: In case you would like to investigate whether a similar…
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
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Identify the two samples as either independent or dependent. 1. Two samples comparing pre and post semester scores for students in a class 2. A sample of air quality measurements taken in the spring and a sample of air quality measurements taken in the fall. 3. A survey comparing couples political beliefs 4. Sample exam means comparing two different classes 5. Before and after comparison of 500 meter run times, when comparing two different exercise programs Write the null and alternative hypothesis for each claim. Remember to use the difference notation D. 1. A statistics instructor claims his teaching can improve your exam scores 2. Using before and after rounds of golf, a coach claims that she can improve your golf game Listed below are heights in inches of fathers and their first sons. 72 73 Father Son Difference 1. Complete the table and find the differences 2. Use a 5% level of significance to test the claim there is no difference in heights between fathers and first sons. Before…
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The October 2019 Gallup Poll reported the proportion of Republicans, Independents, and Democrats who favor the legalization of marijuana. Here are the results: Step 1: Test Set-Up Step 2. Select the Level of Significance, α A 5 percent significance level is selected. Step 3. State the Null Hypothesis (H0) and Alternate Hypothesis (H1) H0: H1: Step 4. Compose the Decision Rule Step 5. Calculate the Value of the Test Statistic, p-value, and estimate statistical power (Use G*Power) Use G*Power to calculate statistical power. Use these settings: Test family: z tests Statistical test: Proportion: Difference between two independent proportions Type of power analysis: Post hoc: Compute achieved power – given α, sample size and effect size Step 6. Decide and Report

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