You are given that Mass of 73Li = 7.0160u, Mass of 42He = 4.0026u and Mass of 11H = 1.0079u. When 20 g of 73Li is converted into 42He by proton capture, the energy liberated, (in kWh), is: [Mass of nucleon = 1 GeV/c2] 1) 6.82 × 105 2) 4.5 × 105 3) 8 × 106 4) 1.33 × 106
You are given that Mass of 73Li = 7.0160u, Mass of 42He = 4.0026u and Mass of 11H = 1.0079u. When 20 g of 73Li is converted into 42He by proton capture, the energy liberated, (in kWh), is: [Mass of nucleon = 1 GeV/c2] 1) 6.82 × 105 2) 4.5 × 105 3) 8 × 106 4) 1.33 × 106
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You are given that Mass of 73Li = 7.0160u,
Mass of 42He = 4.0026u and Mass of 11H = 1.0079u.
When 20 g of 73Li is converted into 42He by proton capture, the energy liberated, (in kWh), is: [Mass of nucleon = 1 GeV/c2]
- 1) 6.82 × 105
- 2) 4.5 × 105
- 3) 8 × 106
- 4) 1.33 × 106
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