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The figure below shows three charged particles at three corners of a rectangle. The particle at upper left has a charge q1 = 4.00 nC, the one at the lower left has a charge of q2 = 5.00 nC,and the one at lower right has a charge q3 = 6.00 nC. The rectangle's horizontal side has length x = 5.00 m and its vertical side has length y = 3.50 m. Find the electric field at the fourth corner.
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- Consider point charge Q₁ positioned in the x-y plane as shown in the figure. y (cm) 90 80 70 60 50 40 30 20 10 0 H Q1 0 10 20 30 40 50 60 70 80 90 x (cm) The point charge has the following value: Q₁ = -35.9 nC. What is the magnitude of the electric field at the position P? 4.360x102 N/C You are correct. Your receipt no. is 159-4863 Ⓒ What is the y-component of the electric field vector at this location? Previous TriesA small rubber sphere has a mass of 3.64 g and a charge of -18.6 µC. It levitates, motionless, when placed in a uniform electric field perpendicular to the ground. What is the magnitude of the electric field (in N/C)? N/C What is the direction of the electric field? O upward O downward O east westThree identical charges (q = -7.0 μC) lie along a circle of radius 3.9 m at angles of 30°, 150°, and 270°, as shown in the figure below. What is the resultant electric field at the center of the circle? 9 N/C 270° 150° 30°
- Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q₁ = -30.00 nC and 92 = 9.00 nC. Express your answer in vector form.) N/C E = -4 92 -2 y (cm) 4 2 -2 -4 2 4 91 x (cm)Problem 6: A positive charge of magnitude Q; = 0.45 nC is located at the origin. A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 12 cm from the origin. The point Pis located y = 18 cm above charge Q2. y R Q2 X ©theexpertta.com Part (a) Calculate the x-component of the electric field at point P due to charge Qj. Write your answer in units of N/C. Ex 1 =2 narrow, flat metal plates are positioned vertically, 20.00 cm. The first plate has a positive charge with charge density σ=+630.0 mC/m2 and a second plate has an equal but opposite negative charge with charge density σ=-6300.0 mC/m2 . There are also two narrow, flat metal plates positioned horizontally, 30.00 cm apart, with the top plate given a negative charge, and the bottom plate given an equal but opposite positive charge, such that the electric potential of the bottom plate is 5.00 V higher than the top plate. A small sphere with a mass of m =64.35 g, and a charge of q =22.00 mC is attached to a narrow, stiff, massless, insulating rod with a length of L= 8.00 cm, which is pivoted at point O, which is 2.000 cm from the second plate. The sphere/rod unit is angled at 5 degrees with horizontal and released from rest. Will the sphere/rod ever hit an angle of 0 degrees with the horizontal? If so, how long will it take to reach that point?
- Three point-like charges are placed as shown in the figure, a = 20.0 cm and b = 66.0 cm. The charge (q) is placed halfway on the (b) side. Find the magnitude of the electric field at the top left corner. Let q1 = −2.00 μC, q2= −3.90 μC,and q3= −3.70 μCAn object having a net charge of 25.9 µC is placed in a uniform electric field of 609 N/C directed vertically up. What is the mass of this object if it “floats" in the field? The acceleration due to gravity is 9.8 m/s?. Answer in units of g.Two point charges are lying on the y- axis as in the figure: q₁ = -4.10 μC and 92 = +4.10 µC. They are equidistant from the point P, which lies on the x- axis. (a) What is the magnitude of net electric field at P? (b) A small object of charge qo = 7.30 µC and mass m = 1.24 g is placed at P. When it is released, what is the magnitude of its acceleration? 91 92 + (a) Number (b) Number 0.880m 31.5 31.5° 0.880 m +x Units Units !!