A particle with a charge of q₁ = -4.0 C is placed 5.0 m away from another charged particle q2 = +9.0 C.Find the magnitude and direction of electric field at point A which is shown in the figure.k = 9.00 x 109 Nm²C29₁ = -4C2 mA5 m45 x 10⁹ N/C (to the left)18 x 10⁹ N/C (to the right)18 x 10⁹ N/C (to the left)45 x 10⁹ N/C (to the left)I3 m92 = +9CLeftRight

Answered: A particle with a charge of q₁ = -4.0 C…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A particle with a charge of q₁ = -4.0 C is placed 5.0 m away from another charged particle q2 = +9.0 C.
Find the magnitude and direction of electric field at point A which is shown in the figure.
k = 9.00 x 109 Nm²
C2
9₁ = -4C
2 m
A
5 m
45 x 10⁹ N/C (to the left)
18 x 10⁹ N/C (to the right)
18 x 10⁹ N/C (to the left)
45 x 10⁹ N/C (to the left)
I
3 m
92 = +9C
Left
Right

Expert Solution

Introduction:

Electrostatic force is force experienced between 2 charged particles owing to the charge present in them. Electric field at a point can be defined as force acting on unit positive test charge kept at that position. It is a vector quantity. It is given by

$E = \frac{k q}{r^{2}}$

Where $q, r$ are charge and distance of point respectively.

We find the field due to each charge and add them vectorially.

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