### Electric Field from Point ChargesGiven the two charged particles shown in the figure below, find the electric field at the origin. Let \( q_1 = -30.00 \text{ nC} \) and \( q_2 = 7.00 \text{ nC} \). Express your answer in vector form.\[ \vec{E} = \boxed{} \text{ N/C} \]#### Diagram Explanation:In the provided graph, there are two charged particles:- **Particle \( q_1 \)**: This particle is represented by a blue dot located at the coordinates (3 cm, 1 cm). It has a charge of \( -30.00 \text{ nC} \).- **Particle \( q_2 \)**: This particle is represented by a red dot located at the coordinates (-2 cm, 2 cm). It has a charge of \( 7.00 \text{ nC} \).The graph is a Cartesian plane with the x-axis and y-axis labeled in centimeters. The point where the electric field is to be calculated is at the origin, which is the (0, 0) point on the graph.

Answered: Image /qna-images/answer/554a3ff4-778b-4e0a-b9d4-6761698dd8b0.jpg

Given the two charged particles shown in the figure below, find the electric field at the origin. (Let 91 = -30.00 nC and 92= 7.00 nC. Express your answer in vector form.) N/C y(cm) 4 91 -4 92 -2 2 4 x (cm)

Given the two charged particles shown in the figure below, find the electric field at the origin. (Let 91 = -30.00 nC and 92= 7.00 nC. Express your answer in vector form.) N/C y(cm) 4 91 -4 92 -2 2 4 x (cm)

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Chapter1: Units, Trigonometry. And Vectors

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### Electric Field from Point Charges

Given the two charged particles shown in the figure below, find the electric field at the origin. Let \( q_1 = -30.00 \text{ nC} \) and \( q_2 = 7.00 \text{ nC} \). Express your answer in vector form.

\[ \vec{E} = \boxed{} \text{ N/C} \]

#### Diagram Explanation:

In the provided graph, there are two charged particles:

- **Particle \( q_1 \)**: This particle is represented by a blue dot located at the coordinates (3 cm, 1 cm). It has a charge of \( -30.00 \text{ nC} \).
- **Particle \( q_2 \)**: This particle is represented by a red dot located at the coordinates (-2 cm, 2 cm). It has a charge of \( 7.00 \text{ nC} \).

The graph is a Cartesian plane with the x-axis and y-axis labeled in centimeters. The point where the electric field is to be calculated is at the origin, which is the (0, 0) point on the graph.

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