Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q₁ = -26.00 nC and 92 = 8.00 nC. Express your answer in vector form.) E N/C 92 -4 -2 y (cm) 4 -2+ 91 2 4 x (cm)
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- The drawing shows a positive point charge g₁, a second point charge g₂ that may be positive or negative, and a spot labeled P, all on the same straight line. The distance d between the two charges is the same as the distance between ₁ and the spot P. With g₂ present, the magnitude of the net electric field at P is twice what it is when q₁ is present alone. Given that q₁ = 0.50 μ C, determine 92. 92 d +91 d PGiven the two charged particles shown in the figure below, find the electric field at the origin. (Let 91 1049001 + 129100j N/C ↑E = 4 92 2 y (cm) 4 № -2 HP 4 2 91 x (cm) = : -26.00 nC and 92 = 4.00 nC. Express your answer in vector form.)Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q₁ = -30.00 nC and 92 = 9.00 nC. Express your answer in vector form.) N/C E = -4 92 -2 y (cm) 4 2 -2 -4 2 4 91 x (cm)