y 10 kN 30 cm 10 cm 50 cm 10 cm 300 cm C A OD=-104.16kPa oc=-62.5kPa OA=-20.84kPa OB=-187.5kPa Hint: Determine the internal forces on the bottom face of the column. Apply the normal stress formula for each corner considering both normal force and moments. ở =+²+ Mcx 1 Mcz 土 Ix BE CAREFUL WITH SIGNS (Positive sign convention is shown below)
y 10 kN 30 cm 10 cm 50 cm 10 cm 300 cm C A OD=-104.16kPa oc=-62.5kPa OA=-20.84kPa OB=-187.5kPa Hint: Determine the internal forces on the bottom face of the column. Apply the normal stress formula for each corner considering both normal force and moments. ở =+²+ Mcx 1 Mcz 土 Ix BE CAREFUL WITH SIGNS (Positive sign convention is shown below)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
An eccentric load is applied to a column as shown. Verify
(show with clear calculations) the normal stress distribution given for
the bottom of the column.
![y
10 kN
30 cm
10 cm
50 cm
10 cm
300 cm
C
A
OD=-104.16kPa
oc=-62.5kPa
OA=-20.84kPa
OB=-187.5kPa
Hint:
Determine the internal forces on the bottom face of the column.
Apply the normal stress formula for each corner considering both normal force and
moments. ở =+2+ Mcx 1 Mcz
Ix
BE CAREFUL WITH SIGNS (Positive sign convention is shown below)
BE CAREFUL WITH “I" AND “c“ VALUES WHICH WILL BE DIFFERENT FOR EACH DIRECTION](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81c49c3a-fd10-4970-b9e9-6159c9b72167%2F6666419c-e0c0-4443-951d-9a82470d08ff%2Fvw9ymmk_processed.png&w=3840&q=75)
Transcribed Image Text:y
10 kN
30 cm
10 cm
50 cm
10 cm
300 cm
C
A
OD=-104.16kPa
oc=-62.5kPa
OA=-20.84kPa
OB=-187.5kPa
Hint:
Determine the internal forces on the bottom face of the column.
Apply the normal stress formula for each corner considering both normal force and
moments. ở =+2+ Mcx 1 Mcz
Ix
BE CAREFUL WITH SIGNS (Positive sign convention is shown below)
BE CAREFUL WITH “I" AND “c“ VALUES WHICH WILL BE DIFFERENT FOR EACH DIRECTION
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