Using the maximum shear stress (MNST) and maximum normal stress theory (MSST) , find the minimum yield strength to be used for the beam shown in the figure(attached). Choose an appropriate material accordingly. T=300 N.m M=250 N.m F=800 N  and Take the safety factor as 2.5

Q: ट ६६ docs.google.com The state of plane stress at a point is represented on the element shown in the…

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are S, = 90 MPa and S, =…

A: Given data in question  Normal stresses as compressive and tensile  Angle No shearing stress To find…

Q: Find the stress distribution in the beam shown in the figure below A, E. I constant

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Q: Learning Goal: To determine the in-plane principal stresses and maximum shear stress along with…

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Q: Consider a 2D state of stress given by: Oz 38 MPa Oy 25 MPa Ozy- 14 MPa If the material has Young's…

A: Given data: σxx=38 Mpaσyy=25 Mpaσxy=14 MpaE=30GPa=30×103 Mpaμ=0.2 Note: shear stress σxy has no…

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Q: A state of stress is specified in the figure shown. Determine the principal stress oy (MPa) if P…

A: The normal stress on vertical plane, P1=-27MpaThe normal stress on horizontal plane, P2=0The shear…

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A: given- flow stress-σ=500ε0.1young modulus E=200 GPathickness=100 mmcompressed to 95 mm

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Q: For the figure below, Determine the following: 10 MPa - 40 MPa 50 MPa The oavg is equal to in MPa:…

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A: The given data is: σx=40 MPaσy=80 MPaζxy=60 MPa

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A: Given- Principal stress- σ1=+1.5σ σ2=+σ σ3=-0.5σ  Elastic limit E=210 MPa, Poisson's ratio- μ=0.3,…

Q: For a given stress tensor 30 30 N/mm? , determine 20 (a) Principal stresses (b) Maximum shear stress

A: From tensor:σx=100Mpaσy=20Mpaτxy=30MpaRadius of the circleR=(σx-σy2)2+τxy2R=(100-202)2+302R=50 MPA…

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Q: 3. The stress element is shown in the figure. Determine the equivalent stress according to the third…

A: Solution: Given: σx=40 MPaσy= 40 MPaτxy=60 MPa Equivalent stress according to third and fourth…

Q: 1: he in-plane principal stresses and ar stress along with their orientations and mal stress for an…

A: Radius of the circleR=(σx-σy2)2+τxy2R=(116+282)2+642R=77.25 MPA

Q: At a point in a machine component that is subjected to plane stress, the normal and shear stresses…

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Q: Question The figure shows the state of stress at a certain point in a stressed body. The magnitudes…

A: Given data- The state of stress- σx=100 MPa,σy=-20 MPa, To Find- The radius of Mohr's stress circle.…

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Q: The state of stress at a point is given by: o= 80 MPa, oy=100 MPa and tauxv =60 MPa. If the yield…

A: State of stresses-σx=80 MPaσy=100 MPaτxy=60 MPayield strength-fy=150 MPa

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Q: The stresses shown act at a point in a stressed body. The stress magnitudes are S, - 70 MPa and Sy =…

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Q: Question- Principal stress at a point in an elastic material are 1.50 (tensile), o (tensile) and…

A: Given- Principal stresses-σ1=+1.5σ σ2=σ σ3=-0.5σ E=210 MPaμ=0.3

Planar Stresses