For a square cross-section bar affected by torsional moment at both ends, the streps components are shown as follows (opposite the figure): a) Find the principal directions for the zero principal stress? b) For the following special case, show that the stress vector on the lateral surface of the rod is zero: 4 = (xỉ - a?xx - a²) %3D c) Also the torsional moment at each of the two ends of the rod is equal to: M = 32 4 = f(x1, X2) %3D 013 ax2 %3D %3D 011 = 022 = 033 = 012 =0 X2
For a square cross-section bar affected by torsional moment at both ends, the streps components are shown as follows (opposite the figure): a) Find the principal directions for the zero principal stress? b) For the following special case, show that the stress vector on the lateral surface of the rod is zero: 4 = (xỉ - a?xx - a²) %3D c) Also the torsional moment at each of the two ends of the rod is equal to: M = 32 4 = f(x1, X2) %3D 013 ax2 %3D %3D 011 = 022 = 033 = 012 =0 X2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![For a square cross-section bar affected by torsional moment at both ends, the stress components are
shown as follows (opposite the figure):
a) Find the principal directions for the zero principal stress?
b) For the following special case, show that the stress vector on the lateral surface of
the rod is zero:
4 = (xỉ – a?xx? - a²)
%3D
c) Also the torsional moment at each of the two ends of the rod is equal to:
M =
32
4 = f(x1, X2)
ax2
011 = 022= 033 = 012 = 0
X2
221 PM
Links 69%
44°F Rain and snow
ENG
1/16/2022](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2d010c38-9149-4308-a53f-a6642a3a7c02%2F4ea32107-9c5f-4c90-8bc0-014da1ba96c7%2Fomincg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a square cross-section bar affected by torsional moment at both ends, the stress components are
shown as follows (opposite the figure):
a) Find the principal directions for the zero principal stress?
b) For the following special case, show that the stress vector on the lateral surface of
the rod is zero:
4 = (xỉ – a?xx? - a²)
%3D
c) Also the torsional moment at each of the two ends of the rod is equal to:
M =
32
4 = f(x1, X2)
ax2
011 = 022= 033 = 012 = 0
X2
221 PM
Links 69%
44°F Rain and snow
ENG
1/16/2022
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