1. The plate below is attached to the vertical surface AB. Its top and bottom surfaces slide smoothly along the horizontal surfaces AD and BC, but are prevented from moving vertically. The plate can move freely in the z- direction (perpendicular to the page). The right side of the plate is uniformly pulled such that it displaces 0.8 mm to the right. The plate is aluminum, which has the following material properties: 150 nim Modulus of Elasticity = 88.5 GPa 150 mum HFo.Bmm Modulus of Rigidity = 34 GPa Poisson Ratio = 0.32

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter14: Material Selection
Section: Chapter Questions
Problem 11ETSQ
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1. The plate below is attached to the vertical surface AB. Its
top and bottom surfaces slide smoothly along the
horizontal surfaces AD and BC, but are prevented from
moving vertically. The plate can move freely in the z-
direction (perpendicular to the page). The right side of the
plate is uniformly pulled such that it displaces 0.8 mm to
the right. The plate is aluminum, which has the following
material properties:
150 nim
BERA
Modulus of Elasticity = 88.5 GPa
%3D
150 num
F0.8mm
Modulus of Rigidity 34 GPa
%3D
Poisson Ratio = 0.32
Transcribed Image Text:1. The plate below is attached to the vertical surface AB. Its top and bottom surfaces slide smoothly along the horizontal surfaces AD and BC, but are prevented from moving vertically. The plate can move freely in the z- direction (perpendicular to the page). The right side of the plate is uniformly pulled such that it displaces 0.8 mm to the right. The plate is aluminum, which has the following material properties: 150 nim BERA Modulus of Elasticity = 88.5 GPa %3D 150 num F0.8mm Modulus of Rigidity 34 GPa %3D Poisson Ratio = 0.32
С.
Determine the normal strain along line BD.
d. Determine the normal stress in the x and y directions. Note that the stain along AC is equal to the
strain along BD. Assume the temperature remains constant. (If you are unable to solve part c, use
normal strain = 0.0025 mm/mm for AC and BD.)
Transcribed Image Text:С. Determine the normal strain along line BD. d. Determine the normal stress in the x and y directions. Note that the stain along AC is equal to the strain along BD. Assume the temperature remains constant. (If you are unable to solve part c, use normal strain = 0.0025 mm/mm for AC and BD.)
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