Answered: X and Y are independent events.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

J and K are independent events. P(J | K) = 0.73. Find P(J) %3D P(J) = %3D Hint: Independent Events Video on Independent Events [+]
A student goes to the library. Let events B= the student checks out a book and D= the student check out a DVD. Suppose that P(B)=0.54 P(D)=0.45 and P(D|B)=0.50 Round each answer to four decimal places. (a) Find P(B′)Enter the exact answer.P(B′)= (b) Find P(D AND B)Enter the exact answer.P(D AND B)= (c) Find P(B|D).Round your answer to three decimal places.P(B|D)= (d) Find P(D AND B′)Enter the exact answer.P(D AND B′)= (e) Find P(D∣B)Enter the exact answer.P(D∣B′)
Let P(A) = 0.4, P(B|A) = 0.5, and P(B|Ac) = 0.25. Compute P(B).
If P(x)=0, this means that A. The event X might occur. B. The event X will occur C. The event X will never occur
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.45, 0.05, 0.45, and 0.05, respectively. (0) Calculate E(X) and then E(5 - X). E(X) - E(5 - X) - 150 (b) Would the repair facility be better off charging a flat fee of $65 or else the amounts (5- X). (Note: It is not generally true that E()- The repair facility Select--- be better off charging a flat fee of s65 because E150 [(5 - x)] -
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.15, 0.15, 0.35, and 0.35, respectively. (a) Calculate E(X) and then E(5 – X). E(X) = E(5 - X) (b) Would the repair facility be better off charging a flat fee of $95 or else the amount $ 150 ? [(5 - X)] Note: It is not generally true that E. E(Y) 150 The repair facility -Select--- v be better off charging a flat fee of $95 because E (5 - X)
Maddy waits tables and has determined that 12% of her tables leave her 12 percent tip, 30% of her tables leave her 15 percent tip, 48% of her tables leave her 18 percent tip, and 10% of her tables leave her 20 percent tip. Fill in the table of values below to find the expected percentage of tips that Maddy receives. (Enter X as a whole number, P(X) as a decimal with two decimal digits, and X*P(X) as a decimal with two decimal digits...THANK YOU) X1 = P(X1) = X1*P(X1) = X2 = P(X2) = X2*P(X2) = X3 = P(X3) = X3*P(X3) = X4 = P(X4) = X4*P(X4) =
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.35, 0.15, 0.35, and 0.15, respectively. (a) Calculate E(X) and then E(5 - X). E(X) E(5-X) = (b) Would the repair facility be better off charging a flat fee of $70 or else the amount $ 150 (5-X) The repair facility ---Select--- be better off charging a flat fee of $70 because E ]= 150 (5-X)] ? Note: It is not generally true that : E ( =) = E(Y)
Of all awarded prizes, 2% are worth $1000, 10% are worth $100, and 88% are worth $10. Let X be the the winnings for a single ticket. Find 1. E(X) (the expected winnings) 2. V(X) 3. E(10X + 2) 4. V(10X + 2)
Find the probability distribution for Y. The table for the probability distribution of Y may have more cells than needed. f(x) = 1/1/20 X f(x) y g(y) -2 Y=X² + 1 -1 0 1 2
For the signal below, sketch the following signals (a) x(t) (b) x(t-2) (c) x(t+2) (d) x(-t) (e) x (2t) (f) x (2t-4) (g) x(4-t) (h) x(t/4) -t-2≤t≤0 x(t)= = t 0≤t≤4 0 otherwise
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively. (a) Calculate E(X) and then E(5 − X). E(X) = E(5 − X) = (b) Would the repair facility be better off charging a flat fee of $110 or else the amount $ 150 (5 − X) ? Note: It is not generally true that E c Y = c E(Y) . The repair facility be better off charging a flat fee of $110 because E 150 (5 − X) =

SEE MORE QUESTIONS

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS

X and Y are independent events. P(X)=0.3; P(Y)=0.4. Find (a) P(X and Y) (b) P(X | Y) (c) P(Y | X) (d) P(X or Y)