Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively. (a) Calculate E(X) and then E(5 − X). E(X) = E(5 − X) = (b) Would the repair facility be better off charging a flat fee of $110 or else the amount $ 150 (5 − X) ? Note: It is not generally true that E c Y = c E(Y). The repair facility be better off charging a flat fee of $110 because E 150 (5 − X) =

Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively. (a) Calculate E(X) and then E(5 − X). E(X) = E(5 − X) = (b) Would the repair facility be better off charging a flat fee of $110 or else the amount $ 150 (5 − X) ? Note: It is not generally true that E c Y = c E(Y). The repair facility be better off charging a flat fee of $110 because E 150 (5 − X) =

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively.

(a)

Calculate

E(X) and then E(5 − X).

E(X)

E(5 − X)

(b)

Would the repair facility be better off charging a flat fee of $110 or else the amount

150

(5 − X)

Note: It is not generally true that E

E(Y)

The repair facility be better off charging a flat fee of $110 because

150

(5 − X)

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