If E[X] = 5 and Var(X) = 4, then E[(4 + 5X)²] = [] and Var(3+5X) 0
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![If E[X] = 5 and Var(X) = 4, then
E[(4 + 5X)²] = []
and
Var(3+5X)
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d69634b-8a8a-4609-8704-3bdadaefe256%2F79dab78c-7301-4afc-827e-807342fa33ac%2F15tho5_processed.png&w=3840&q=75)
Transcribed Image Text:If E[X] = 5 and Var(X) = 4, then
E[(4 + 5X)²] = []
and
Var(3+5X)
0
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