For mutually exclusive events R₁, R₂, and R3, we have P(R₁) = 0.05, P(R₂) = 0.5, and P(R3) = 0.45. Also,P(Q|R₁) = 0.5, P (Q | R₂) = 0.7, and P (Q | R3) : = 0.4. Find P (R₁ | Q).P(R₁ IQ) =(Type an integer or a simplified fraction.)

P(R1) = 0.05P(R2) = 0.5P(R3) = 0.45P(Q|R1) = 0.5P(Q|R2) = 0.7P(Q|R3) = 0.4P(R1|Q) = ?

Answered: For mutually exclusive events R₁, R₂,…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

(d) If we define the events A and B by: A = {(X,Y):2(Y – X) > Y + X} Determine P(ĀN B).
In a game, five cards are drawn out of a deck of 52 cards. If the result is a four-of-a-kind, you stop the game. Otherwise, you put the cards back into the deck and shuffle it to continue the game. Let X be the number of draws in the game. Compute E(X) and Var(X).
A and B are independent events. If Pr[A]=0.3 and Pr[B]=0.7, what is Pr[A∩B′]?
A coin is tossed twice. Let Z denote the number of heads on the first toss and W the total number of heads on the 2 tosses. If the coin is unbalanced and a head has a 40% chance of occurring, find (a) P( W=2 | Z= 1) (b) P( Z=0 | W = 1) ; (c) are Z and W independent?
lecture(12.11A): Researchers were interested in the effects of co-sleeping on nightime waking and crying in infants. .They assesed the number of minutes parents reported that their infants were awake and crying for a period of three days. Five of the infants co-slept with thier mothers(Co) and four infants slept in crib(Cr).The researchers wanted to see if there was a difference in the total number of minutes of crying during the 3 nights. for the two groups. A summary of the data is given below Co-sleepers night time crying in minutes: 8, 4, 7, 7, 6 Crib-sleepers night time crying in minutes: 30, 17, 22, 25 Test the hypotheses at (aplha=.05) level of signifcance. using the 5 step hypotheses testing procedure. Clealy state the null and alternative hypotheses. Round your answer to 2 decimal places.
Suppose that a decision maker's risk atitude toward monetary gains or losses x given by the utility function(x) = (50,000+x) 34/2. Suppose that a decision maker has the choice of buying a lottery ticket for $5, or not. Suppose that the lottery winning is $1,000,000, and the chance of winning is one in a thousand. Then..... O The decision maker should not buy the ticket, as the utility from not buying is 223.6, and the expected utility from buying is 223.59. The decision maker should not buy the ticket, as the utility from not buying is 223.6067, and the expected utility from buyingis 223.6065. O The decision maker should buy the ticket, as the utility from not buying 223.60, and the utility from buying is 224.4. The decision maker should buy the ticket, as the utility from not buying 223.6065, and the utility from buying is 223.6067.
Consider the following function for a value of k.f(x) ={3kx/7, 0 ≤ x ≤ 1 3k(5 − x)/7 , 1 ≤ x ≤ 30, otherwise.Comment on the output of these probabilities below, what will be theconclusion of your output.(i)Evaluate k.(ii)find (a) p(1 ≤ x ≤ 2) (b) p(x > 2). (u) p(x ≤ 8/3).
J and K are independent events. P(J | K) = 0.23. Find P(J)
(8) X and Y are independent events. P(X)=0.3; P(Y)=0.4. Find (a) P(X and Y) (b) P(X | Y) (c) P(Y | X) (d) P(X or Y)
For a person selected randomly from a certain population, events A and B are defined as follows. A = event the person is maleB = event the person is a smoker For this particular population, it is found that P(A) = 0.49, P(B) = 0.26, and P (A ∩ B) = 0.15. Find P (A ∪ B). Round approximations to two decimal places.
J and K are independent events. P(J|K) = 0.6. Find P(J).
I got the right calculations for p(x=0) and p(x=1) but I can’t seem to get 2,3, and 4 even though I’m using the same steps. Can you please show me where I’m making an error. Thank you!

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

For mutually exclusive events R₁, R₂, and R3, we have P(R₁) = 0.05, P(R₂) = 0.5, and P(R3) = 0.45. Also, P(Q|R₁) = 0.5, P (Q|R₂) = 0.7, and P (Q|R3) = 0.4. Find P P(R₁ 1Q) = (Type an integer or a simplified fraction.) IP(R₁ IQ).