Ri R2 3352 3л 6л Alt I Vth =Vi x = Ve 2V ZV √3 4V ww V1 =2V R1 3 R2 602 V2 -7V R ≤≤ 4V V3 R3 402

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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I need help,

how can I do kvl in this direction

As I doing the Thevenin’s Theorem to solve for the current through resistor R3 (4Ω)  and the power dissipated by R3

Ri
R2
3352
3л
6л
Alt
I
Vth
=Vi x = Ve
2V
ZV
√3
4V
Transcribed Image Text:Ri R2 3352 3л 6л Alt I Vth =Vi x = Ve 2V ZV √3 4V
ww
V1
=2V
R1
3
R2
602
V2
-7V
R
≤≤
4V
V3
R3
402
Transcribed Image Text:ww V1 =2V R1 3 R2 602 V2 -7V R ≤≤ 4V V3 R3 402
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