Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:Equal #include #include using namespace std; int main() { double targetValue; double sensorReading; cin >> targetValue; cin >> sensorReading; if (/* Your solution goes here */) { cout << "Equal" << endl; } else { cout << "Not equal" << endl; } return 0; }

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:Equal #include #include using namespace std; int main() { double targetValue; double sensorReading; cin >> targetValue; cin >> sensorReading; if (/* Your solution goes here */) { cout << "Equal" << endl; } else { cout << "Not equal" << endl; } return 0; }

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter4: Making Decisions

Section: Chapter Questions

Problem 8RQ: What is the output of the following code segment?inte=5,f=10;if(eff0)Write(Purple)...

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