If the input is negative, make numltemsPointer be null. Otherwise, make numltemsPointer point to numltems and multiply thevalue to which numltemsPointer points by 10. Ex: If the user enters 99, the output should be:Items: 990368400.2174782.qx3zqy71 #include 2 using namespace std;34 int main() {int* numItemsPointer;int numItems;78cin >> numItems;9.10V* Your solution goes here*/11nullptr) {if (numItemsPointercout <« "Items is negative" << endl;}else {12==131415

I have provided C++ CODE along with CODE SCREENSHOT and also provided TWO OUTPUT…

If the input is negative, make numltemsPointer be null. Otherwise, make numltemsPointer point to numltems and multiply the value to which numltemsPointer points by 10. Ex: If the user enters 99, the output should be: Items: 990

If the input is negative, make numltemsPointer be null. Otherwise, make numltemsPointer point to numltems and multiply the value to which numltemsPointer points by 10. Ex: If the user enters 99, the output should be: Items: 990

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

If the input is negative, make numltemsPointer be null. Otherwise, make numltemsPointer point to numltems and multiply the
value to which numltemsPointer points by 10. Ex: If the user enters 99, the output should be:
Items: 990
368400.2174782.qx3zqy7
1 #include <iostream>
2 using namespace std;
3
4 int main() {
int* numItemsPointer;
int numItems;
7
8
cin >> numItems;
9.
10
V* Your solution goes here
*/
11
nullptr) {
if (numItemsPointer
cout <« "Items is negative" << endl;
}
else {
12
==
13
14
15

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