Write a short explanation for the following terms: 1. Tensile, Compressive and Shear Loads 2. Bending, Torsion and Buckling 3. Stress
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- c. Determine critical load and critical stress for the column/axial member. Justify selection of the formulas for the calculationsInformation provided: i) Boundary/end conditions: In this instance, the column is assumed to be fixed at both ends, simulating conditions where the column is integrally connected to the floor slabs above and below, a common condition in many mechanical design contexts. ii) External axial load: Assuming the column supports a floor with a uniformly distributed load, we've calculated the total axial load on the column to be 453.589 kN. iii) Properties of the column: The cylindrical column is composed of steel, a commonly used material with a known Young's modulus (E) of approximately 200 GPa. The steel has a yield stress of around 250 MPa and ultimate stress near 400 MPa. The diameter (d) of the column is 0.3048 m, providing a cross-sectional area (A) of π*(d/2)² = 0.073 m².Hi, I have been given this pin-jointed frame analysis to solve (see pictures of the structure attached). Can you help me answer all the questions below? Especially the one about the bending moment and shear force. The Figure 2 attached is a simplified structure to undertake a structural analysis on a concept design for a low cost stroller/buggy for children. The buggy consists of a number of metal sections that are pin-jointed together. The buggy is designed to accommodate a child of mass no more than 20 kg, sat on the seat which is supported at four points (Fc) on the frame of the buggy. Assume that the weight of the child is equally distributed across all of the points indicated on Figure 2 as Fc. Assume that there are no additional forces applied to the handle of the buggy, that the buggy is static (stationary) and that the buggy, and the elements of the frame have no mass. At points A and G, there are roll supports. At Points B, F and D there are the pin supports. I am required…Learning Goal: To use Hooke's law to determine the value of an axial load applied to a rectangular shape and to determine its lateral expansion. The element shown below is subjected to the axial compressive force P, which causes the shape to contract longitudinally in the direction a distance of 8 = 0.720 mm. Let h = 144.5 mm, w = 88.50 mm, and L = 298.0 mm. Assume the element is made from steel that has a modulus of elasticity of E= 200 GPa and a value of Poisson's ratio of v=0.32. ♥ Part A Value of the axial load Determine the value of the axial load P. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) P = Submit P μÀ Value Units ? Part B Lateral expansion in the y direction Determine the lateral expansion in the y direction due to the axial load. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) dy = Submit d₂ = Value Part C - Lateral expansion in the z direction μA Submit…
- Q 3(a) A block of weight 1 kN is attached to a string which passes over a smooth pulley. When a weight of W = 500 N is attached to the string as shown in Figure Q3(a), the block is on the point of moving. Perform the following; (1) draw free body diagram; (ii) determine the coefficient of friction; (ii) normal force; (iv) frictional force. Pulley 50° 1 kN W Figure Q3(a) (b) If the angle of inclination of the string connecting pulley and the block is increased, explain its effect on normal force and frictional force, assuming the weight of the block remains same. Refer to Figure Q3(a).Problem parameters for Case #2: Cases Load (lbs) 2 55,000 What is the total Deformation in (in) on the rod? Note: • Give your answer rounded to 3 decimal place i.e. 0.04352 = 0.044 or 0.04342 = 0.043 • Do NOT include any units or other text. The size of your numeric value should be given in (in). i.e. if your answer is 0.043 (in) then enter this as "0.043" (Do NOT enter "0.043 in")2: Answer briefly the following: 1- The method of joints is used to analyze and design trusses. This method is based on what? (For section A only) 2- Define Simple Truss. (For evening section only) 3- The method of sections is used to analyze and design trusses. This method is based on which principle? (For section B only)
- 1. A 0.015 meter diameter bar of steel is stress tested and the following stress-strain curve is produced Stress (psix 10 60 50 8 20 10 1 MPa 300 100 psi (x 10%) 50 200-30 OL 40- 20- 10 0.05 0.005 1 L 0.010 0.10 Strain a. What is the ultimate tensile strength (MPa)? d. What is the yield strength(MPa)? 0.15 c. What is the percent plastic elongation at the time of fracture? e. What is the Modulus of Elasticity (GPa)? 400 300 200 Stress (MPa) b. What is the greatest load that can be place on this bar before failure(N)? 100 10 0.20B. PROBLEM ON TOPIC "COLUMNS": A round steel rod made of AISI C1020 as rolled is to support a load of 10,500 lbs. Let L= 40 inches, both ends are fixed. If loading is gradually repeated in one direction with mild shock (static approach), determine the following: 1. Diameter using Euler's formula: 2. Diameter using Johnson's formula: 3. What diameter are you going to use and why? Selected Dia.: Why? Answer: Answer: 4. How much load can be applied in kips before buckling occurs on the preferred size in item 3? Answer:The material is a spring wire has a shear modulus of 1.2 x 107 lbf/in2. The maximum allowable stress under design conditions is 50,000 lbf/in2. The spring index is 7. Assume the maximum stress is experienced when a 700 lbm object falls from a height of 46 in above the tip of the spring, impacts squarely on the spring, and deflects the spring 10 in. Determie:1. The minimum wire diameter is most nearlyA. 0.58 in B. 0.88 in C. 1.4 in D. 1.8 in2. The mean coil diameter is most nearlyA. 8.6 in B. 10 in C. 13 in D. 16 in3. The number of active coils is most nearlyA. 8 B. 11 C. 12 D. 14
- What is the cross sectional area necessary to carry a 50 ton force (tensile load) in a square bar with a tensile strength of 80000 ibs/sq in?Two concentric springs are constructed with squared and ground ends from oil-hardened steel. The ultimate strength for the steel is 204,000 lbf/in². The steel's yield strength is to be estimated as 75% of the ultimate strength. The shear modulus for the steel is 11.5 x 106 lbf/in². The springs support a static force of 150 lbf. The spring dimensions and properties are as follows: Inner spring Wire diameter: 0.177 in Mean coil diameter: 1.5 in Total number of coils: 12.75 Free length: 4.5 in Outer spring Mean coil diameter: 2.0 in Wire diameter: 0.2253 in Free length: 3.75 in Total number of coils: 10.25 1. The deflection of the inner spring is most nearly A. 2.0 in B. 2.4 in C. 2.9 in D. 3.1 in 2.The maximum force exerted by the inner spring is most nearly A. 57 lbf B. 67 lbf C. 79 lbf D. 86 lbf 3. The maximum shear stress in the inner spring is most nearly A. 47 kips/in² B. 52 kips/in² C. 57 kips/in² D. 64 kips/in² 4. The factor of safety in shear for the inner spring is most nearly…Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025