THE PROGRAM SHOULD BE WRITTEN USING C++CheckpointsAbsolutely no arrays or structures. The problem is designed to be solved using primitive types only: int, float, double, char.Use only pass by value.Also, ABSOLUTELY NO GLOBAL VARIABLE DECLARATIONS.All variables need to be declared in main() or another function. # Irvine Ranch Water District## OverviewThe task is to write a C++ program designed to estimate your water bill for the upcoming month. The program utilizes your water meter, which measures water usage in hundreds of cubic feet (CCF). Notably, one CCF corresponds to approximately 748 gallons of water.### Program Input Requirements- All inputs and their corresponding prompts must be included within the `main()` function, as the lab exercise only allows for pass-by-value usage.- Your program should request the following information from the user: - **Number of residents in the household**: This should be an integer greater than 0. - **Type of residence**: The user will input a character to specify the residence type: - `S` for Single-family Residence - `C` for Condo - `A` for Apartment - **Actual number of CCFs used**### Important Considerations- The program is designed to be case-insensitive. For instance, if a user enters a lowercase `s`, the program should process it as an uppercase `S`. This can be achieved by employing the `toupper()` function or using an `if` statement.- If the user inputs a negative number for the number of residents, the program should display an error message and terminate.- Similarly, if the user enters any letter other than `S`, `s`, `C`, `c`, `A`, or `a`, an error message should be displayed, and the program should end.By following these guidelines, the program will accurately estimate the user's water bill based on their actual usage, residence type, and household size. **Calculation of Bill Amount**This calculation will be completed in two separate functions, each called from `main()`.### First Calculation Function**Step 1: Calculate Budget for People**- Allow 50 gallons per person, per day (assuming a 30-day month).- Example for 4 people: \[ 50 \times \text{people} \times 30 / 748 = 50 \times 4 \times 30 / 748 = 8.02 \]**Step 2: Calculate Water Budget for Outdoor Landscape**| Type of Residence | Budget for Outdoor Usage ||--------------------------|--------------------------|| Single-family Residence | 2.30 || Condo | 0.75 || Apartment | 0.00 |**Budget Total Calculation:**\[\text{Budget Total} = \text{budget for people} + \text{budget for landscape} = 8.02 + 2.30 = 10.32\]### Second Calculation FunctionCalculate cost as follows:- $1.65 per CCF used under or equal to their water budget.- $4.83 per CCF on the amount of water used above their water budget.

round() is function used to round the value to next decimal The final output is displayed with 2 point precision #include<iostream> #include<cmath> #incllude<iomanip> using namespace std; double function1(int numberOfResidents,char typeOfResidence){ double budget=round((50*numberOfResidents*30*100)/(double)748); //convert to cubic feet multiplied by 100 and rounded budget=budget/100; //divided the above result by 100 for the result to be 2 point precision if(typeOfResidence=='S' || typeOfResidence=='s') budget+=2.3; //add 2.3 to budget if type is s or S else if(typeOfResidence=='C' || typeOfResidence=='c') budget+=0.75; //add 0.75 to budget if type is C or c return budget; //return same budget otherwise} double function2(double usedCCFs,double budget){ if(usedCCFs<=budget) return 1.65*usedCCFs; //if usage is less than budget multiply 1.65 with usage else return (1.65*budget)+4.83*(usedCCFs-budget); //1.65 for usage till budget and 4.83 for remaining usage} int main(){ int numberOfResidents; char typeOfResidence; double usedCCFs; cout << "Enter number of residents: "; cin >> numberOfResidents; cout << "S-Single Family residence \nC-Condo \nA-Apartment \nEnter type of residence: " ; cin >> typeOfResidence; cout << "Enter total usage: "; cin >> usedCCFs; if(numberOfResidents>0){ //if residents is positive integer if(typeOfResidence=='A'||typeOfResidence=='S'||typeOfResidence=='C' ||typeOfResidence=='a'||typeOfResidence=='s'||typeOfResidence=='c'){ //if any of 6 characters double budget=function1(numberOfResidents,typeOfResidence); //call function1 double billAmount=function2(usedCCFs,budget); //call function2 cout << "The total bill amount is $" << fixed << setprecision(2) <<billAmount <<endl; //display total with 2 point precision } else cout << "Invalid type of residence" << endl; //if residence type is other than 6 } else //if residents enetered is less than or equal to 0 cout << "Number of residents cannot be neagtive" << endl; return 0;}