Wooden elements can be connected using adhesive, contact or penetration type connections. Source: Author (2024). Based on your knowledge of connections and splices, evaluate the connection of wooden pieces shown in Figure 1 below: Figure 1: Connecting wooden pieces. Source: Author (2024). ​Consider that the connected pieces are made of sweet cedar wood, whose longitudinal compression resistance of the fibers is equivalent to 31.5 MPa. Its wood is 2nd category, being subjected to a load of medium duration and class 1 humidity. The boards are 5 cm thick and are connected by two connectors with a diameter equal to 9.5 mm and yield stress equal to 600 MPa . Determine the type of failure that could occur and the resistance of the connection and select the correct alternative. Form:Blim=1.25. square root of fyd/fedB= t/d  AlternativesAlternative 1:Failure due to pin bending; 2.1 kN. Alternative 2:Failure due to pin bending; 4.3 kN. Alternative 3:Failure due to wood inlay; 2.7 kN. Alternative 4:Failure due to wood inlay; 5.5 kN. Alternative 5:Failure due to wood inlay; 27.4 kN.

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter12: Composite Materials
Section: Chapter Questions
Problem 10ETSQ
Question

Wooden elements can be connected using adhesive, contact or penetration type connections.

Source: Author (2024).

Based on your knowledge of connections and splices, evaluate the connection of wooden pieces shown in Figure 1 below:

Figure 1: Connecting wooden pieces.

Source: Author (2024).

​Consider that the connected pieces are made of sweet cedar wood, whose longitudinal compression resistance of the fibers is equivalent to 31.5 MPa. Its wood is 2nd category, being subjected to a load of medium duration and class 1 humidity. The boards are 5 cm thick and are connected by two connectors with a diameter equal to 9.5 mm and yield stress equal to 600 MPa . Determine the type of failure that could occur and the resistance of the connection and select the correct alternative.


Form:
Blim=1.25. square root of fyd/fed
B= t/d

 
Alternatives
Alternative 1:
Failure due to pin bending; 2.1 kN.

Alternative 2:
Failure due to pin bending; 4.3 kN.

Alternative 3:
Failure due to wood inlay; 2.7 kN.

Alternative 4:
Failure due to wood inlay; 5.5 kN.

Alternative 5:
Failure due to wood inlay; 27.4 kN.

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