Why is the following situation impossible? A uniform beam of mass m = 3.00 kg and length = 1.00 m supports blocks with masses m₁ = 5.00 kg and m₂ = 15.0 kg at two positions as shown in the figure below. The beam rests on two triangular blocks, with point P a distance d = 0.300 m to the right of the center of gravity of the beam. The position of the object of mass m₂ is adjusted along the length of the beam until the normal force on the beam at O is zero. m₁ CG

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Chapter1: Units, Trigonometry. And Vectors
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Why is the following situation impossible? A uniform beam of mass m 3.00 kg and length = 1.00 m supports blocks
with masses m₁ = 5.00 kg and m₂ = 15.0 kg at two positions as shown in the figure below. The beam rests on two
triangular blocks, with point P a distance d = 0.300 m to the right of the center of gravity of the beam. The position of the
object of mass m, is adjusted along the length of the beam until the normal force on the beam at O is zero.
m₁
O
2
CG
m.
=
Transcribed Image Text:Why is the following situation impossible? A uniform beam of mass m 3.00 kg and length = 1.00 m supports blocks with masses m₁ = 5.00 kg and m₂ = 15.0 kg at two positions as shown in the figure below. The beam rests on two triangular blocks, with point P a distance d = 0.300 m to the right of the center of gravity of the beam. The position of the object of mass m, is adjusted along the length of the beam until the normal force on the beam at O is zero. m₁ O 2 CG m. =
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