Answered: A wood plank has a length of 4.2 m an

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A wood plank has a length of 4.2 m an

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Three children are trying to balance on a seesaw, which consists of a fulcrum rock, acting as a pivot at the center, and a very light board 3.4 m long (Figure 1). Two playmates are already on either end. Boy A has a mass of 45 kg, and boy B a mass of 35 kg. ▼ Part A Where should girl C, whose mass is 25 kg, place herself so as to balance the seesaw? Express your answer to two significant figures and include the appropriate units. for Part A for Part Addo for Part redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A x= Value Units
Review Conceptual Example 7 before starting this problem. A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 462 N walk on the overhanging part of the plank before it just begins to tip? 41.1 ma
A uniform, 20-kg, 8.0-m-long, wooden plank that is parallel to level ground is supported by two pivots: one pivot is at the extreme left end of the plank, and the other pivot is 3.0 m inward from the extreme right end of the plank. A 80-kg construction worker, who is initally standing on the extreme left end of the plank, begins to walk to the right. How far from the right end of the plank will the worker be located when the plank begins to tip? 4.0 m 4.0 m 5.0 m a. 4.50 m O b.5.00 m O c. 4.25 m d. 5.25 m O e. 4.75 m
A beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (b) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = (c) Check the answer to part (e) by computing torques around the first pivot point.x = (d)Except for possible slight differences due to rounding, is the answer the same for F and E?
A tightrope walker is walking between two buildings holding a pole with length ?=15.5 m, and mass ??=19.5 kg. The daredevil grips the pole with each hand a distance ?=0.575 m from the center of the pole. A bird of mass ??=525 g lands on the very end of the left‑hand side of the pole. Assuming the daredevil applies upward forces with the left and right hands in a direction perpendicular to the pole, what magnitude of force ?left and ?right must the left and right hand exert to counteract the torque of the bird?
The diagram above shows a 3.00 m long uniform beam. The left end of the beam is attached to a wall by a frictionless pivot. The beam is supported by a string that keeps the beam horizontal. The string makes an angle of 35.0° relative to vertical. The beam has a mass of 7.00 kg. A 2.00 kg mass is located at the end of the beam. A 6.00 kg mass is located 1.00 m from the 2.00 kg mass, as shown in the diagram. a. What is the tension in the string? b. What is the y-component of force applied to the beam by the pivot?
Consider a teeter-totter that is made out of pine, shown below. A pineapple sits on one side of the teeter-totter, a distance 1.38 m from the pivot point, while an apple (non-pine) sits on the other side, a distance of 2.65 m from the pivot. If the pineapple has a mass 125 g, what must the mass of the apple be in order to balance the teeter-totter (i.e. to maintain rotational equilibrium)? [Answer in units of grams (g) with 3 sig figs but do not enter units with your answer]
Scenario: A heavy kid and a light kid are at the two ends of a see-saw, modeled as a long thin rod with point masses at each end, pivoted at the middle. The see-saw is tilted from horizontal. See-saw end-to-end length: 4.5 meters See-saw mass: 15 kg Heavy kid's mass: 39 kg Light kid's mass: 25 kg Tilt angle: 14 degrees (a) What is the magnitude of the net torque on the see-saw due to gravity, in newton-meters? N m (b) What is the moment of inertia of the two-kid system about the pivot at the center of the see-saw? kg m2 (c) What is the magnitude of the see-saw's angular acceleration at this instant? rad/s?
You're carrying a 3.4-m-long, 24 kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35 cm from its tip. How much force must you exert to keep the pole motionless in a horizontal position?
A beam resting on two pivots has a length of L = 6.00 m and mass M = 94.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 51.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a)Where is the woman when the normal force n1 is the greatest? x = _____m(b) What is n1 when the beam is about to tip?____N(c) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip.____N
A wood plank (length 4.4 m and mass 13.0 kg) is balanced between two saw horses, as shown in the figure below. One saw horse is positioned directly under one end of the plank, and the other is located a distance d1 = 3.4 m away. A child (mass 25 kg) walks along the plank, as if it were a balance beam. What is the furthest distance d2 (in meters) from the end of the plank that the child can walk before the plank tips and falls? Hint: When the plank starts to tip, one of the forces becomes zero.